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2 years ago

3x+5⁰ 2x-25⁰ supplementary angles

Mathematics

2 answers:

Makovka662 [10]2 years ago

5 0

Answer:x=40

Step-by-step explanation:

5x-20=180

5x=200

X=40

lorasvet [3.4K]2 years ago

3 0

Answer:

x=40, ∠ACB=125, ∠ACD= 55

Step-by-step explanation:

In order to solve this, you have to find the x-value. We know that these angles are supplementary, which means that the angles, ∠ACB and ∠ACD, both add up to 180°.

With this information, we can conclude 3x+5+2x-25=180.

To solve this equation for x,

1. Combine like terms

5x-20=180

2. Add 20 to both sides

5x=200

3. Divide both sides by 5.

x=40

Now we have the x-value. All we have left to do is plug that in to both of the equations for the angles.

1. ∠ACB: 3(40)+5

120+5

∠ACB = 125

2. ∠ACD: 2(40)-25

80-25

∠ACD = 55

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Answer: 108 ft³

Step-by-step explanation:

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7 0

1 year ago

Read 2 more answers

Math:

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

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Step-by-step explanation:

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2 years ago

3x+5⁰ 2x-25⁰ supplementary angles​

3x+5⁰ 2x-25⁰ supplementary angles