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Nastasia [14]
3 years ago
14

A photo of a beetle in a science book is increased to 535​% as large as the actual size. If the beetle is 14 ​millimeters, what

is the size of the beetle in the​ photo?
Mathematics
1 answer:
AnnZ [28]3 years ago
4 0

Answer: 74.9 millimeters

Step-by-step explanation:

From the question, a photo of a beetle in a science book was.increased to 535​% as large as its actual size and the beetle.has a actual size of 14 ​millimeters,

The size of the beetle on the photo will be 535% of 14 millimeters. This will be:

= 535% of 14

= 535/100 × 14

= 5.35 × 14

= 74.9 millimeters

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Irrational conjugate theorem
podryga [215]

Answer:

The irrational conjugate theorem states that if a polynomial equation has a root (a + √b), then we can say that the conjugate of (a + √b), i.e. (a - √b) will also be another root of the polynomial.

Step-by-step explanation:

The irrational conjugate theorem states that if a polynomial equation has a root (a + √b), then we can say that the conjugate of (a + √b), i.e. (a - √b) will also be another root of the polynomial.

For example, if we consider a quadratic equation x² + 6x + 1 = 0, then two of its roots are - 3 + √8 and - 3 - √8 and they are conjugate of each other. (Answer)

7 0
3 years ago
Pls just type it in no files pls and thank you
Nana76 [90]

Answer:

31

Step-by-step explanation:

First type of clay required 3 cups of flour per batch

She made 5 batches

5 * 3 = 15

So she used 15 cups of flour for the first type of clay

Second kind of clay required 4 cups of flour per batches

She made 4 batches

4 * 4 = 16

So she used 16 cups of flour for the second type of clay

we now add the total number of cups of flour used for each type of clay

16 + 15 = 31

She used a total of 31 cups of flour

5 0
3 years ago
Against the wind a small plane flew 715 miles in 2 hours and 10 minutes. The return trip took only 1 hour and 50 minutes. What w
ZanzabumX [31]

Answer:

  360 mi/h

Step-by-step explanation:

The speed for the outbound trip was ...

  speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h

The inbound speed was ...

  (715 mi)/(1 5/6 h) = 390 mi/h

The airspeed of the plane is the average of these two ground speeds, so is ...

  (330 +390)/2 = 360 . . . . mi/h

8 0
3 years ago
Find the distance between the two points S (-5,-2) and T (-3,4).
icang [17]

Answer:

d =2 \sqrt{10}

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS

<u>Algebra II</u>

  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

S (-5, -2)

T (-3, 4)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(-3+5)^2+(4+2)^2}
  2. Add:                              d = \sqrt{(2)^2+(6)^2}
  3. Evaluate:                      d = \sqrt{4+36}
  4. Add:                              d = \sqrt{40}
  5. Simplify:                       d =2 \sqrt{10}
6 0
3 years ago
What linear function represents the line given by the point slope equation y+7= 2/3(x+6)?
aleksandrvk [35]

Answer:

The graph of the line in the attached figure

Step-by-step explanation:

we have

y+7=\frac{2}{3}(x+6)

This is the equation of a line into point slope form

The slope is m=\frac{2}{3}

The line pass through the point (-6,-7)

To graph the line find the y-intercept

Remember that

The y-intercept of the line is the value of y when the value of x is equal to zero

so

For x=0

y+7=\frac{2}{3}(0+6)

y+7=\frac{2}{3}(6)

y+7=4

y=4-7=-3

The y-intercept is the point (0,-3)

with the point (-6,-7) and (0,-3) plot the line

see the attached figure

8 0
3 years ago
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