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Nastasia [14]
3 years ago
14

A photo of a beetle in a science book is increased to 535​% as large as the actual size. If the beetle is 14 ​millimeters, what

is the size of the beetle in the​ photo?
Mathematics
1 answer:
AnnZ [28]3 years ago
4 0

Answer: 74.9 millimeters

Step-by-step explanation:

From the question, a photo of a beetle in a science book was.increased to 535​% as large as its actual size and the beetle.has a actual size of 14 ​millimeters,

The size of the beetle on the photo will be 535% of 14 millimeters. This will be:

= 535% of 14

= 535/100 × 14

= 5.35 × 14

= 74.9 millimeters

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Answer:

Option b is correct.

The common ratio for the given geometric sequence is; \frac{-1}{2}

Step-by-step explanation:

The given sequence is;  -96, 48 , -24, 12 , -6, .....

Since, given sequence is Geometric

Geometric Sequence in which each term is found by multiplying the previous term by a constant(i.e common ratio)

In general we write geometric sequence as;

a , ar, ar^2, ar^3 , .....

where a be the first term and r is the common ratio.

On comparing the given sequence with general geometric sequence;

we get

a = -96                  ......[1]

ar = 48                   ......[2]

ar^2 = -24              .....[3]

and so on....        

To find the common ratio i.e, r;

Divide equation [2] by [1];

\frac{ar}{a} =\frac{48}{-96}

Simplify:

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by dividing the equation [3] by [2] we get;

\frac{ar^2}{ar} = \frac{-24}{48}

Simplify:

r = \frac{-1}{2}

As, you can see that the value of r is constant i.e, r= \frac{-1}{2} in the given sequence.

Therefore, the common ratio for the given geometric sequence is; r= \frac{-1}{2}


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3 years ago
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Step-by-step explanation:

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Answer:

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