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katrin [286]
3 years ago
7

A store is advertising a 25% off sale. Mikale purchases a swimming pool for $225. What was the original price of the pool?

Mathematics
1 answer:
DIA [1.3K]3 years ago
7 0

Answer:

B

Step-by-step explanation:

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Rewrite in simplest terms: (-8x + 5) - (x – 7)​
Ilia_Sergeevich [38]

Answer:

-9x+12

Step-by-step explanation:

(-8x + 5) - (x – 7)​

Distribute the minus sign

(-8x + 5) - x + 7

Combine like terms

(-8x -x+ 5+7) ​

-9x +12

7 0
3 years ago
Read 2 more answers
Can someone please help me.. very quickly .. thank you
Alisiya [41]
X/8 + 12 = 16 
start by subtracting twelve from both sides
x/8 + 12 = 16 
      - 12   -12
You're left with x/8 = 4
Multiply both sides by 8
8× x/8 = 4 ×8
Your answer is x = 32
If you need to simplify, the answer is 2. 


 
3 0
3 years ago
Read 2 more answers
У= 3х-5<br> у = 3х+12<br> Please help ASAP for my lil sister
exis [7]

Answer:

0

Step-by-step explanation:

The equation is undefined.

4 0
2 years ago
Need Help On This Problem PLZ :-)
anastassius [24]

Answer:

y = 9 + 19x

Step-by-step explanation:

To find the equation matching a set of data, you simply try a few values for x and see if by solving that side of the equation you get the value of y.  If you do, you found your equation.

You have a big advantage here... since you have the value of y when x = 0.

When x = 0, y = 9, that's a very important data to have to simplify your research.

Let's try the value of 0 for x in each of the given equations:

y = 18 + 10 (0) = 18  --- NO

y = 9 + 19 (0) = 9 --- YES!  We can confirm with another value of x:

y = 9 + 19 (1) = 28 --- YES! Confirmed!

y = 9 + 19x is your answer!

8 0
3 years ago
the half-life of chromium-51 is 38 days. If the sample contained 510 grams. How much would remain after 1 year?​
madam [21]

Answer:

About 0.6548 grams will be remaining.  

Step-by-step explanation:

We can write an exponential function to model the situation. The standard exponential function is:

f(t)=a(r)^t

The original sample contained 510 grams. So, a = 510.

Each half-life, the amount decreases by half. So, r = 1/2.

For t, since one half-life occurs every 38 days, we can substitute t/38 for t, where t is the time in days.

Therefore, our function is:

\displaystyle f(t)=510\Big(\frac{1}{2}\Big)^{t/38}

One year has 365 days.

Therefore, the amount remaining after one year will be:

\displaystyle f(365)=510\Big(\frac{1}{2}\Big)^{365/38}\approx0.6548

About 0.6548 grams will be remaining.  

Alternatively, we can use the standard exponential growth/decay function modeled by:

f(t)=Ce^{kt}

The starting sample is 510. So, C = 510.

After one half-life (38 days), the remaining amount will be 255. Therefore:

255=510e^{38k}

Solving for k:

\displaystyle \frac{1}{2}=e^{38k}\Rightarrow k=\frac{1}{38}\ln\Big(\frac{1}{2}\Big)

Thus, our function is:

f(t)=510e^{t\ln(.5)/38}

Then after one year or 365 days, the amount remaining will be about:

f(365)=510e^{365\ln(.5)/38}\approx 0.6548

5 0
2 years ago
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