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allsm [11]
3 years ago
7

a right triangle has a 30 degree angle. the leg adjacent to the 30 degree angle measures 25 inches. what is the length of the ot

her leg?
Mathematics
1 answer:
crimeas [40]3 years ago
8 0
The length of the other leg is 14.4
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OMG PLZZZZ HELP ME!! I NEED DA ASMWER ASAP!!
kogti [31]

Answer:

I am not sure but I would say rectangular prisim

Step-by-step explanation:

8 0
2 years ago
Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona
andrey2020 [161]

Answer:

a. v.v' = v₁v₂ -  v₁v₂ = 0 b.  (20, -21)/29 and  (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' =  (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j  

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

=  v₁v₂ -  v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

8 0
2 years ago
Solve for :<br>(x+3)/2=6​
Marianna [84]

Answer:

x=9

Step-by-step explanation:

(x+3)/2=6​

Multiply each side by 2

2*(x+3)/2=6*2

x+3 = 12

Subtract 3 from each side

x+3-3 = 12-3

x = 9​

5 0
2 years ago
The temperature outside in the morning was 15 degrees below zero. By lunchtime it was 25 degrees above zero. How many degreees d
denpristay [2]

15 degrees below zero = -15

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It rose 40 degrees.

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3 years ago
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Aleksandr [31]
The answer is c
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