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Sergeeva-Olga [200]
3 years ago
9

If a ∥ b and e ∥ f, what is the value of y? 87 88 91 92

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

88 i believe

Step-by-step explanation:

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What is the equation of the line that passes through the point (5,3) and has a slope<br> of?
klio [65]

Answer:

slope=2

I think that you can use demos it is a calculator just put the point and you get the answer

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2 years ago
Solve each equation. Check your solution.<br><br> 7a+10=2a
Debora [2.8K]

Answer:

a = -2

Step-by-step explanation:

7a + 10 = 2a

subtract 7a from each side

7a-7a+10 = 2a-7a

10 = -5a

divide by -5

10/-5 = -5a/-5

-2 = a

check

7 (-2) +10 = 2(-2)

-14 + 10 = -4

-4 = -4

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3 years ago
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2 5/8 times 1 1/7 equals
Alex17521 [72]
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6 0
3 years ago
Read 2 more answers
Consider the surface f (x comma y comma z )f(x,y,z)equals=negative 2 x squared plus 2 y squared minus 3 z squared plus 3 equals
trapecia [35]

Answer:

a) (8,8,-6)

b) 4x+4y+3z = -3

Step-by-step explanation:

a)

The surface is given by the equation  

f(x,y,z) = 0 where

f(x,y,z)=-2x^2+2y^2-3z^2+3

The gradient of this function is the vector

(\frac{\partial f}{\partial x},\frac{\partial f}{\partial y},\frac{\partial f}{\partial z})=(-4x,4y,-6z)

If we evaluate it in the point P = (-2,2,1) we obtain the point

(8,8,-6)

b)

The vectors with their tails at P are of the form  

(-2,2,1)-(x,y,z) = (-2-x, 2-y, 1-z)

as they must be orthogonal to the gradient, they must be orthogonal to the vector (8,8,6) so their inner product is 0

(-2-x,2-y,1-z)\cdot(8,8,6)=0\Rightarrow -16-8x+16-8y+6-6z=0\Rightarrow 4x+4y+3z=-3

and the equation of the desired plane is

4x+4y+3z = -3

3 0
4 years ago
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