All categories

2 years ago

Nina can braid 144 inches of rope in 3 hours find her unit rate round your answer to the nearest thousand

Mathematics

1 answer:

Alex777 [14]2 years ago

7 0

Answer:

48 inches

0.8 minutes

Step-by-step explanation:

To find the unit rate of inches per hour, divide 144 by 3.

144÷3=48

You don't need to round because there are no decimals.

To find the time to braid 1 inch, first multiply 3 by 60 (because there are 60 minutes in 1 hour).

3×60=180

Then divide 144 by 180.

144÷180= 0.8

You don't need to round because there are no thousandths.

You might be interested in

Evaluate the triple integral ∭EzdV where E is the solid bounded by the cylinder y2+z2=81 and the planes x=0,y=9x and z=0 in the

dem82 [27]

Answer:

I = 91.125

Step-by-step explanation:

Given that:

$I = \int \int_E \int zdV$ where E is bounded by the cylinder $y^2 + z^2 = 81$ and the planes x = 0 , y = 9x and z = 0 in the first octant.

The initial activity to carry out is to determine the limits of the region

since curve z = 0 and $y^2 + z^2 = 81$

∴ $z^2 = 81 - y^2$

$z = \sqrt{81 - y^2}$

Thus, z lies between 0 to $\sqrt{81 - y^2}$

GIven curve x = 0 and y = 9x

$x =\dfrac{y}{9}$

As such,x lies between 0 to $\dfrac{y}{9}$

Given curve x = 0 , $x =\dfrac{y}{9}$ and z = 0, $y^2 + z^2 = 81$

y = 0 and

$y^2 = 81 \\ \\ y = \sqrt{81} \\ \\ y = 9$

∴ y lies between 0 and 9

Then $I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \int^{\sqrt{81-y^2}}_{z=0} \ zdzdxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{z^2}{2} \end {bmatrix} ^ {\sqrt {{81-y^2}}}_{0} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{(\sqrt{81 -y^2})^2 }{2}-0 \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \int^{\dfrac{y}{9}}_{x=0} \begin {bmatrix} \dfrac{{81 -y^2} }{2} \end {bmatrix} \ dxdy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81x -xy^2} }{2} \end {bmatrix} ^{\dfrac{y}{9}}_{0} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81(\dfrac{y}{9}) -(\dfrac{y}{9})y^2} }{2}-0 \end {bmatrix} \ dy$

$I = \int^9_{y=0} \begin {bmatrix} \dfrac{{81 \ y -y^3} }{18} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \int^9_{y=0} \begin {bmatrix} {81 \ y -y^3} \end {bmatrix} \ dy$

$I = \dfrac{1}{18} \begin {bmatrix} {81 \ \dfrac{y^2}{2} - \dfrac{y^4}{4}} \end {bmatrix}^9_0$

$I = \dfrac{1}{18} \begin {bmatrix} {40.5 \ (9^2) - \dfrac{9^4}{4}} \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 3280.5 - 1640.25 \end {bmatrix}$

$I = \dfrac{1}{18} \begin {bmatrix} 1640.25 \end {bmatrix}$

I = 91.125

4 0

3 years ago

I'm being Timed please hurry.

koban [17]

Answer:

D. 45 degree counterclockwise rotation

Step-by-step explanation: :

The original image is triangle TUV and it has been rotated counter clockwise to form triangle T'U'V' using the origin as the center of rotation. . The rotation is 45 degrees rotation.

Hence, option B is correct.

Plz mark brainliest!

6 0

2 years ago

The formula for the area of a square is s2, where s is the side length of the square. What is the area of a square with a side l

jonny [76]

Answer:

step by step

given length=6

so area of square is given by s2 i.e 6^2

=6×6

=36 (Ans)

8 0

3 years ago

What is 1/9+2/18?????????????????????????????????

Wittaler [7]

Answer:

2/9

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Help me get the answer and explain your answer.

max2010maxim [7]

Answer:

Step-by-step explanation:

eq. of any line with slope m and passing through (x1,y1) is

y-y1=m(x-x1)

reqd. eq. is

y-1=3/4(x-2)

4y-4=3x-6

4y=3x-6+4

4y=3x-2

so 3.

3 0

3 years ago