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solniwko [45]
3 years ago
5

To find the distance between a point X and an inaccessible point , a line segment XY is constructed. Measurements show that XY =

975m , angle XYZ=22^ 42^ prime and angle YZX=105^ 18^ prime . Find the distance between X and Z to the nearest meter.
Mathematics
1 answer:
svlad2 [7]3 years ago
5 0

Answer:

sorry i didn't not answer

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After 8 examinations, Kacey's average was 55. Her next result increased her average to 60. What was the next score?
Yuki888 [10]

Answer:

65

Step-by-step explanation:

they're going by 5s every time her score increases. hope I helped (:

5 0
2 years ago
(9.2 x 102) x (7.1 x 104)
gulaghasi [49]

Answer:

692914.56

Step-by-step explanation:

(9.2 x 102)

= 938.4

(7.1 x 104)

= 738.4

938.4 x 738.4

=

692914.56

8 0
3 years ago
Read 2 more answers
WILL GIVE A BRAINLEST
Gnoma [55]

Answer: "No, the triangles are not necessarily congruent." is the correct statement .


Step-by-step explanation:

In ΔCDE, m∠C = 30° and m∠E = 50°

Therefore by angle sum property of triangles

m∠C+m∠D+m∠E=180°

⇒m∠D=180°-m∠E-m∠C=180°-30°-50°=100°

⇒m∠D=100°

In ΔFGH, m∠G = 100° and m∠H = 50°

Similarly m∠F +∠G+m∠H=180°

⇒m∠F=180°-∠G-m∠H=180°-100°-50=30°

⇒m∠F=30°

Now ΔCDE and ΔFGH

m∠C=m∠F=30°,m∠D=m∠G=100°,m∠E=m∠H=50°

by AAA similarity criteria  ΔCDE ≈ ΔFGH but can't say congruent.

Congruent triangles are the pair of triangles in which corresponding sides and angles are equal . A congruent triangle is a similar triangle but a similar triangle may not be a congruent triangle.


8 0
3 years ago
Read 2 more answers
Can anyone help please
Lyrx [107]

Answer: u<u>h sorry no can do</u>

Step-by-step explanation:

7 0
2 years ago
Oleg ran 8.8 miles in 1 hour and 20 min. Assuming he continues at a constant rate ,how long will it take him to run any number o
hammer [34]

Calculate his running rate in miles per hour:-

1 hour and 20 minutes = 4/3 hours.

His mph = 8.8 / 4/3 = 8.8 * 3/4 = 6.6 mph

Time = distance / rate

Time to run any number of miles ( n miles) = n / 6.6


5 0
3 years ago
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