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tamaranim1 [39]
3 years ago
15

Steps to describe an inscribed regular hexagon.

Mathematics
1 answer:
Rus_ich [418]3 years ago
5 0

Answer:

many sides

unique shape

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Iii. Divide and simplify if possible.<br> 7)<br> 5V2u y2<br> V 18uv4<br> 8)<br> 3V 50x’y<br> V2.xy
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Ummm let’s see......

3xy(1/3)
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3 years ago
If -7(y-3)= -14. What is the value of x?
pickupchik [31]

Answer:

none

Step-by-step explanation:

no x because (y-3)=14 so the x wouldnt repeat

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3 years ago
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What is the z-score of a value that is 2.08 standard deviations greater than the mean ?
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4 years ago
A rectangular garden 50 feet long and 10 feet wide is enclosed by a fence. To make the garden larger, while using the same fence
ivann1987 [24]

The area of the rectangular garden is 50 x 10 = 500 square feet.

The perimeter of the rectangular garden is 50 + 50 + 10 +10 =120 feet.

The perimeter of the square also needs to be 120 because it is using the same amount of fence.

Divide 120 by 4 sides: 120/4 = 30

Each side of the square garden would need to be 30 feet.

The area of a square is Side^2, 30^2 = 900 square feet.

The square is 900 - 500 = 400 square feet more.

3 0
3 years ago
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Find the projection of u = &lt;–6, –7&gt; onto v = &lt;1, 1&gt; a. &lt;-13/2,-13/2&gt; b. &lt;39,91/2&gt; c. &lt;-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

5 0
3 years ago
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