All categories

2 years ago

PLEASE HELP!!!! Find the volume. Round to the nearest tenth, if necessary.

Mathematics

1 answer:

Aleksandr [31]2 years ago

4 0

Answer:

$63cm {}^{3}$

Step-by-step explanation:

the shape above is a cuboid and volume of a cuboid

= length x breath x height

=length=3cm

breath= 7cm

height= 3cm

volume= (3x7x3)cm =63 cm^3

You might be interested in

Gabby is buying flowers for a friend. She can choose daisies, carnations, or sunflowers. She can put the flowers in a clear, red

In-s [12.5K]

Answer:

Daisies: Clear vase

Carnations: Red vase

Sunflowers: Blue vase

Step-by-step explanation:

Your using all the objects and is is in all the combinations.

8 0

3 years ago

Read 2 more answers

What is the slope of the line that passes through the points (2,0) and

Y_Kistochka [10]

Answer:

slope = - $\frac{1}{6}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (2, 0) and (x₂, y₂ ) = (32, - 5)

m = $\frac{-5-0}{32-2}$ = $\frac{-5}{30}$ = - $\frac{1}{6}$

3 0

3 years ago

Read 2 more answers

Games at a carnival cost $3. prizes awarded to winners cost $145.65. how many games must be played to make $50

stich3 [128]

Answer:

Step-by-step explanation:

3×1405 and $.65

8 0

3 years ago

9. If f(x)=x². g(x)=2x-1. and h(x) =find the following.

postnew [5]

Answer:

Please see the attached picture ! :D

-------- HappY LearninG <3 ----------

8 0

2 years ago

Find the length of the curve y = 3/5x^5/3 - 3/4x^1/3 + 6 for 1 < = x < = 8. The length of the curve is . (Type an exact an

Mashutka [201]

Answer:

$\sqrt\frac{387}{20}$

Step-by-step explanation:

$Arc Length =\int\limits^a_b {\sqrt{1+(\frac{dy}{dx})^2 } } \, dx$

$y=\dfrac{3}{5}x^{\frac{5}{3}}- \dfrac{3}{4}x^{\frac{1}{3}}+6$

$\frac{dy}{dx} =x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}}$

$1+(\frac{dy}{dx})^2 }=1+(x^{\frac{2}{3}}-\dfrac{1}{4}x^{-\frac{2}{3}})^2\\=1+(x^{\frac{4}{3}}-\dfrac{1}{2}+ \dfrac{1}{16}x^{-\frac{4}{3}})$

$=\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}}$

For the Interval $1\leq x\leq 8$

Length of the Curve $=\int\limits^8_1 {\sqrt{\dfrac{1}{2}+x^{\frac{4}{3}}+ \dfrac{1}{16}x^{-\frac{4}{3}} } } \, dx\\$

Using T1-Calculator

$=\sqrt\frac{387}{20}$

3 0

3 years ago