Supposse that the distance from the point 
to the point 
is equal to the distance from to the point 
. Then, by the formula of the distnace we must have
cancel the square root and the 
's, and then expand the parenthesis to obtain
then, simplifying we obtain
therfore we must have
this means that the points satisfying the propertie must have first component equal to 5. So we can give a lot of examples of such points: 
. The set of this points give us a straight line and the points (3,0) and (7,0) are symmetric with respect to this line.
6x+5= 9x-4
9=3x
3=x
To find RS you need to substitute x back into the equation
9(3)-4
27-4
23
23 is the answer
Travel direction 3i + 2j, slope = 2/3.
We have slope and a point (-2,1) this gives us a line equation:
LINE BEFORE THE TURN, EQUATION: y = (2/3)x + 1
The point of intersection of the two lines:
1) through (-2,1) with slope 2/3 and;
2) through (-1,6) with slope 3/2.
Answer:
b
Step-by-step explanation:
The range are the values that y can take.
From the graph we can see that all defined values of y are below the x- axis
Thus range is y < 0 → b
