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3 years ago

I need help with this question

Mathematics

1 answer:

Dmitry_Shevchenko [17]3 years ago

8 0

The hypotenuse is 15
The opposite is 12
The adjacent is 9

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If v = 6i + 3j, what is ||-10v||

tia_tia [17]

The values of ||-10v|| is 51.96 units

Complex numbers are square roots of negative numbers. They are expressions that consist of both the real and imaginary axis.

The general form of a complex number is expressed as z = x + iy

Given the complex number v = 6i + 3j,

10v is expressed as 10(6i + 3j)

10(6i + 3j) = 60i + 30j

Take the modulus of the complex number:

$|10v|=\sqrt{60^2+30^2}\\|10v|= \sqrt{1800+900}\\|10v|= \sqrt{2700} \\|10v|=51.96units$

Hence the values of ||-10v|| is 51.96 units

Learn more on the complex numbers here: brainly.com/question/10662770

6 0

3 years ago

Wait is it 43 or 41 pushups ?? I'm confused

SashulF [63]

Its 43 pushups cause the number of pushups are going up by 3

8 0

3 years ago

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It's just a simple equation but the transversal has me stuck

alexgriva [62]

Answer:

x = 22

Step-by-step explanation:

∠VSR and ∠SRU are same- side interior angles and are supplementary, thus

5x + 4 + 44 + x = 180, that is

6x + 48 = 180 ( subtract 48 from both sides )

6x = 132 ( divide both sides by 6 )

x = 22

3 0

3 years ago

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PLEASE HELP I AM SO CONFUSED

Natasha2012 [34]

Answer:

a) h(3) = 9

b) h(0) = 6

c) h(6) = 4

Step-by-step explanation:

Piecewise functions have multiple pieces of curves/lines where each piece corresponds to its definition over an interval.

Given piecewise function:

$\sf h(x)=\begin{cases}\sf \dfrac{x^2-36}{x-6} &\textsf{if }x\neq 6\\\\\sf 4 & \textsf{if }x=6\end{cases}$

Therefore, the function has two definitions:

$\sf h(x)=\dfrac{x^2-36}{x-6} \quad \textsf{when x does not equal 6}$

$\sf h(x)=4 \quad \textsf{when x equals 6}$

Part (a)

h(3) means to substitute x = 3 into the function.

As x does not equal 6, substitute x = 3 into the first piece of the function:

$\begin{aligned}\sf \implies h(3) & =\sf \dfrac{(3)^2-36}{(3)-6}\\\\ & = \sf \dfrac{9-36}{-3}\\\\ & = \sf \dfrac{-27}{-3}\\\\ & = \sf 9\end{aligned}$

Part (b)

h(0) means to substitute x = 0 into the function.

As x does not equal 6, substitute x = 0 into the first piece of the function:

$\begin{aligned}\sf \implies h(0) & =\sf \dfrac{(0)^2-36}{(0)-6}\\\\ & = \sf \dfrac{0-36}{-6}\\\\ & = \sf \dfrac{-36}{-6}\\\\ & = \sf 6\end{aligned}$

Part (c)

h(6) means to substitute x = 6 into the function.

As x equals 6, then use the second piece of the function:

$\sf \implies h(6)=4$

Learn more about piecewise functions here:

brainly.com/question/11562909

brainly.com/question/28151925

7 0

1 year ago

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Chelsea makes $10.55 an hour working at Dr. Daleson’s Car Clinic. She plans to buy a camera, which costs $393.40. Write and solv

inessss [21]

10.55h is greater than or equal to 393.40

5 0

3 years ago

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