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GuDViN [60]
3 years ago
11

Please answer Due in 10 min.​

Mathematics
2 answers:
Lorico [155]3 years ago
8 0
I believe the answer is B
AysviL [449]3 years ago
6 0
I think it is BBBBBBBB
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What would be the value of 150 after eight years if you earn 12 percent interest per year
Monica [59]
The answer depends on what type of interest. If you are using compound interest, then the interest is different every year, as the amount you earn goes up because the amount you have in the bank goes up. Simple interest is the opposite, as you earn one amount each year, and it does not change.
So.....
Simple Interest:
0.12 * 150 = 18
18 * 8 = 144
144 + 150 = $294
Compound Interest:
150(1 + 0.12)^8
150 * 1.12^8
150 * 2.475 = $371
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3 years ago
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Henlo please help!?! Thanks!!<br> ASAP? :D
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Answer:

6 feet

Step-by-step explanation:

Volume = w × h × l

120 = 4 × 5 × l

l = 120 / 20

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40. Find UW.<br> T<br> 6<br> 5<br> U +-<br> The measure of UW is<br> type your answer...
Ahat [919]

Answer:

9

Step-by-step explanation:

UT^2 = UV * UW

6^2 = (x - 7)(x - 7 + 5)

36 = (x - 7)(x - 2)

36 = x^2 - 2x - 7x + 14

x^2 - 9x - 22 = 0

(x - 11)(x + 2) = 0

x - 11 = 0  or  x + 2 = 0

x = 11

UW = x - 7 + 5

UW = 11 - 7 + 5

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2x-7/4 - 1-x/6=17<br> What is the answer?
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The list below shows the Highlight in inches of the player on a man college basketball team
boyakko [2]

We have the data set:

{79, 83, 82, 78, 79, 77, 80, 73, 82, 72}

This data set has 10 items.

To complete the data summary is helpful to sort the data:

{72, 73, 77, 78, 79, 79, 80, 82, 82, 83}

The minimum value is 72.

<em>The quartile divides the data set in 4 parts. </em>

<em>The first quartile is the value for which 25% of the data is below.</em>

<em>The second quartile is the value for which 50% of the data is below. The second quartile is equivalent to the median.</em>

<em>The third quartile is the value for which 75% of the data is below.</em>

In this data set, as its size is a even number, the quartile fall between two positions, so we will calculate the average of this numbers.

The first quartile will fall in the position 0.25*10=2.5. Then we can calculate the 1st quartile as the average between the 2nd and 3rd number of the data set.

This values are 73 (2nd position) and 77 (3rd position), so the average is:

Q_1=\frac{73+77}{2}=75

We can repeat this with the other quartiles:

\begin{gathered} Q_2=M=\frac{79+79}{2}=79 \\ Q_3=\frac{82+82}{2}=82 \end{gathered}

Then:

The first quartile is 75.

The median (second quartile) is 79.

The third quartile is 82.

The maximum value is 83.

7 0
1 year ago
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