Answer:
All options apply to the question because each one reflects one side of technology in relation to the artist's case (that could be a software engineer or a even a hardware designer).
Explanation:
Letter a applies to the question in terms of computer program's behavior with no people's assistance, which is something not real for the present time, although it is easy to imagine that it is going to be a reality in a near future for all the improvements engineers and developers have made. Letter b also applies because computers and softwares have become one of the most important tools for artists around the world, whether for researching and/or for sharing and/or selling their productions, however it is a radical idea to think an artist is not necessary anymore, that is similiar to say human beings are not necessary only because machines have improved. Letter c also applies to the question for all improvements made in art and art forms after all improvements made in technology and tools for technologies development. And, letter d also applies because computers may be used for studying and/or working, which is the perfect tool for a workplace, and this is why it has become essential in many organizations, companies, subsidiaries, agencies, schools, and more.
Answer:
// program in Python to check perfect number
#function to find number is perfect or not
def is_Perfect_Number(n):
#total variable
tot = 1
i = 2
#sum of all divisor of number
while i*i<=n:
if n%i==0:
tot = tot + i + n/i
if tot == n and n != 1:
return 1
i = i+1
return 0
#read until user enter a perfect number
while True:
#read integer
num = int(input("Input an integer: "))
#call the function
if(is_Perfect_Number(num)):
print(num,"is perfect number")
#if perfect number break
break
else:
print(num,"is not a perfect number")
#ask again
print("try again.")
Explanation:
Read number from user and then call the function is_Perfect_Number() with parameter "num".This will find the sum of all divisor of number.If sum is equal to number then it will return 1 else return 0.If the number is not perfect then it will again ask to enter a number until user enter a perfect number.
Output:
Input an integer: 24
24 is not a perfect number
try again.
Input an integer: 28
28 is perfect number
Read and write. Think of the term "literacy rate" it refers to how much of a population can read and write.
Answer:
2
Explanation:
The second option is the only one that will work. The last would work but doesn't make the code any shorter.
Answer:
void delete_record(student_record *arr, int &size, int age, string name, double gpa) {
int index = -1;
if (arr != NULL && size > 0) {
for (int i = 0; i < size; ++i) {
if (arr[i].age == age && arr[i].name == name && arr[i].gpa == gpa) {
index = i;
break;
}
}
}
if (index != -1) {
for (int i = index; i < size - 1; ++i) {
arr[i] = arr[i + 1];
}
size--;
}
}
