Question

given sin A =3/-/34 and that angle S is in quadrant 1, find the exact value of tan A in simplest radical form using a rational denominator

Answer 1

Answer:

$\tan(A) = \frac{3}{5}$

Step-by-step explanation:

Given

$\sin(A) = \frac{3}{\sqrt {34}}$

$0 \le A \le 90$ --- First Quadrant

Required

Find tan(A)

The sin of an angle is:

$\tan(A) = \frac{Opposite}{Hypotenuse}$

and

$\sin(A) = \frac{3}{\sqrt {34}}$

By comparison:

$Opposite = 3$

$Hypotenuse = \sqrt{34$

So, the Adjacent is:

$Hypotenuse^2 = Adjacent^2 + Opposite^2$

$(\sqrt{34})^2 = Adjacent^2 + 3^2$

$34 = Adjacent^2 + 9$

Collect like terms

$Adjacent^2 =34 - 9$

$Adjacent^2 =25$

Take square roots

$Adjacent =\sqrt{25$

$Adjacent =5$

The tangent of an angle is:

$\tan(A) = \frac{Opposite}{Adjacent}$

This gives:

$\tan(A) = \frac{3}{5}$