29, 30, 31
consecutive integers have a difference of 1 between them
let the 3 integers be n, n + 1, n + 2
then n + n + 2 = 60
2n + 2 = 60 ( subtract 2 from both sides )
2n = 58 ( divide both sides by 2 )
n = 29 ← least integer
thus the 3 integers are 29, 30, 31
Answer:
Step-by-step explanation:
Angle B and angle F are known to be equal.
Since angles DCE and DEC are equal, angles ACB and GEF are also equal (vertically opposite angles)
When two angles are equal, the third angle has to be equal too because total angle of both triangles is the same, i.e 180
Now when angles are equal, if we just show that lengths BC ans EF are also equal, it would be sufficient to say that the two triangles are congruent.
Since triangle DCE is an isosceles triangle (because two angles same),
Length CD = ED
We know that
Length of BD = Length FD
Length CD = Length ED
Length of BC = BD - CD
Length of EF = FD - ED
Therefore,
Length BC = Length EF
When all angles are equal, and even one pair of corresponding lengths is equal.. the triangles are congruent
Answer:
B) 3 1/3
Step-by-step explanation:
To divide the fractions, simply follow these steps.
First, flip the second fraction, so that the numerator is the denominator, and the denominator is the numerator. Change the division sign into a multiplication:
(2/3)/(1/5) = (2/3) * (5/1)
Next, multiply straight across:
(2/3) * (5/1) = (2 * 5)/(3 * 1) = 10/3
Finally, simplify. Change the improper fraction into a mixed:
10/3 = 3/3 + 3/3 + 3/3 + 1/3 = 3 1/3
B) 3 1/3 is your answer.
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