Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.
What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So
has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Angles in a triangle must add up to 180, so the missing angle inside the triangle is 180 - (70 + 40), which is 70.
Angles on a straight line (i.e. the line BD) must add up to 180, and because we know part of that angle is 70, x must be 180 - 70, which is 110.
Hence, x is 110 degrees.
Answer:
Step-by-step explanation:
Given a binomial experiment with n trials and probability of success p,
Since each term of the summation is multiplied by x, the value of the term corresponding to x = 0 will be 0. Therefore the expected value becomes:
Now,
Substituting,
Factoring out the n and one p from the above expression:
Representing k=x-1 in the above gives us:
This can then be written by the Binomial Formula as: