Pls help

X 2.2.PS-15

Stella [2.4K]

Answer:

$6.36 would be your answer￣へ￣

7 0

3 years ago

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For each ordered pair (x,y) determine whether it is a solution to the inequality 7x+2y>_26

MA_775_DIABLO [31]

The inequality is given as,

$7x+2y>-26$

Consider that any ordered pair (x,y) is said to be the solution of the inequality if the ordered pair gives a true result when substituted in the inequality.

Consider the ordered pair (4,-9),

$\begin{gathered} 7(4)+2(-9)>-26 \\ 28-18>-26 \\ 10>-26 \end{gathered}$

Clearly, the result is true. So it can be concluded that (4,-9) is a solution of the given inequality.

Therefore, mark YES for the ordered pair (4,-9).

Consider the ordered pair (3,4),

$\begin{gathered} 7(3)+2(4)>-26 \\ 21+8>-26 \\ 29>-26 \end{gathered}$

Clearly, the result is true. So it can be concluded that (3,4) is a solution of the given inequality.

Therefore, mark YES for the ordered pair (3,4).

Consider the ordered pair (-4,0),

$\begin{gathered} 7(-4)+2(0)>-26 \\ -28+0>-26 \\ -28>-26 \end{gathered}$

Clearly, the result is false as -28 is not actually greater than -26.

So it can be concluded that the ordered pair (-4,0) is not a solution of the given inequality.

Therefore, mark NO for the ordered pair (-4,0).

Consider the last ordered pair (-6,8),

$\begin{gathered} 7(-6)+2(8)>-26 \\ -42+16>-26 \\ -26>-26 \end{gathered}$

Note that the numbers on both sides of the inequality are identical. So there should be the symbol of equality, not inequality. So, it can be concluded that this ordered pair (-6,8) is not a solution of the given inequality.

Therefore, mark NO for the ordered pair (-6,8).

4 0

2 years ago

Can someone help me for question 18 pls? I really need help to solve this question!!

earnstyle [38]

Plug the x-values from the table into the given equation and solve for y.

y = 5 - x²

First column

replace x with -2

y = 5 - (-2)²

= 5 - (4)

= 1

(x, y) = (-2, 1)

Second column

replace x with -1

y = 5 - (-1)²

= 5 - (1)

= 4

(x, y) = (-1, 4)

Third column

replace x with 0

y = 5 - (0)²

= 5 - (0)

= 5

(x, y) = (0, 5)

Fourth column

replace x with 1

y = 5 - (1)²

= 5 - (1)

= 4

(x, y) = (1, 4)

Fifth column

replace x with 2

y = 5 - (2)²

= 5 - (4)

= 1

(x, y) = (2, 1)

3 0

4 years ago

A line is defined by the equation y = negative x + 3. Which shows the graph of this line? On a coordinate plane, a line goes thr

andrew-mc [135]

Answer:

A

A line is defined by the equation y =

negative x + 3

. Which shows the graph of this line? On a coordinate plane, a line goes

through points (0, 3) and (3, 0).

On a coordinate plane, a line goes through points (0, negative 3) and (0, 3).

On a coordinate plane, a line goes through points (0, 0) and (2, 6). On a coordinate plane, a line

goes through points (negative 2, 6) and (0,

5 0

3 years ago

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Find the value(s) of the variable(s). Write your answer(s) in simplest radical form.

Romashka [77]

Answer:

Step-by-step explanation:

12). By applying Pythagoras theorem in the given right triangle,

Hypotenuse² = (Leg 1)² + (Leg 2)²

x² = 7² + 7²

x² = 2(7)²

x = $\sqrt{2(7)^{2} }$

x = $7\sqrt{2}$

13). By sine rule,

sin(60)° = $\frac{\text{Opposite side}}{\text{Hypotenuse}}$

$\frac{\sqrt{3}}{2}=\frac{9\sqrt{3} }{y}$

y = $\frac{18\sqrt{3} }{\sqrt{3} }$

y = 18

By cosine rule,

cos(60)° = $\frac{\text{Adjacent side}}{\text{Hypotenuse}}$

$\frac{1}{2}=\frac{x}{y}$

x = $\frac{y}{2}$

x = $\frac{18}{2}=9$

14). By applying Pythagoras theorem in the given right triangle,

12² = x² + x²

144 = 2x²

72 = x²

x = √72

x = 6√2

5 0

4 years ago