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GaryK [48]
3 years ago
9

PLEASE HELP... What do you do when none of the variables cancel out while solving systems by elimination?

Mathematics
1 answer:
Vitek1552 [10]3 years ago
3 0

Answer:

multiply one or both of the equations until a variable can cancel out

You might be interested in
You measure the width of your door to be 36 inches . The truth width of the door is 35.75 inches what is the relative error in y
ElenaW [278]

Answer:

The measurement was off by 0.7%

Step-by-step explanation:

To find the relative error in the measurement, start by finding the difference.

36 - 35.75 = 0.25

Now divide that by the actual measurement of the door.

0.25/35.75 = 0.7%

4 0
4 years ago
Read 2 more answers
The defect length of a corrosion defect in a pressurized steel pipe is normally distributed with mean value 28 mm and standard d
Misha Larkins [42]

Answer:

14.69% probability that defect length is at most 20 mm

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 28, \sigma = 7.6

What is the probability that defect length is at most 20 mm

This is the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 28}{7.6}

Z = -1.05

Z = -1.05 has a pvalue of 0.1469

14.69% probability that defect length is at most 20 mm

5 0
4 years ago
Solve algebraically the simultaneous equations<br><br> X^2 + Y^2 =25<br> Y-2X = 5
Georgia [21]

Answer:

Therefore the solutions are

x=0\\and\\ y =5\\\\Or\\\\x=-4\\and\\y=-3

Step-by-step explanation:

Given:

x^{2} + y^{2} =25 .........( 1 )

y-2x = 5\\y=2x+5     ................( 2 )

To Find:

x = ?

y = ?

Solution:

Substituting ' y ' in Equation  1 we get

x^{2}+(2x+5)^{2} =25

Using identity (A+B)²=A²+2AB+B² we get

x^{2}+4x^{2}+20x+25=25\\\\5x^{2}+20x=0\\5x(x+4)=0\\5x=0\ or\ x+4=0\\x=0\ or\ x= -4

Now Substitute x =0 in equation 2 we get

y=2\times 0+5=5

Or

Now Substitute x =-4 in equation 2 we get

y=2\times -4+5=-3

Therefore the solutions are

x=0\\and\\ y =5\\\\Or\\\\x=-4\\and\\y=-3

4 0
4 years ago
Help I don’t know the answer (only answer if you know what it truly is)
svetoff [14.1K]
So how you find the x-intercept is is by replacing y, with 0 and solve
to find the y-intercept, you replace x with 0 and solve
x-int:
0=-3x+12
-12=-3x
x=4 --> (4,0)
y-int: 
y=-3(0)+12
y=0+12
y=12 --> (0,12)
6 0
3 years ago
Five more than twice a number is 17
Ierofanga [76]
5+2x=17 is the inequality.
5 0
4 years ago
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