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iren [92.7K]
3 years ago
13

(x^3+x^2-9x-6)÷(x^2-9) using long division? How would I solve?

Mathematics
1 answer:
GarryVolchara [31]3 years ago
6 0
The answer is (x + 1) + 3/(x^2-9)
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x-mid-pt = (x₁+x₂)/2

y-mid-pt = (y₁+y₂)/2

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So

midpoint JK = (-1+1/2, 1+3/2) = (0,2)

midpoint KL = (1+5/2, 3+⁻1/2) = (3,1)

midpoint LM = (5+⁻3/2, ⁻1+⁻1/2) = (1,-1)

midpoint MJ = (⁻3+⁻1/2, -1+1/2) = (-2,0)


use the eqn to find distance:


d = √(x₂ - x₁)² + (y₂ - y₁)²


Distance between JK and LM = √(0⁻1)² + (2 - ⁻1)² = √1 + 9 = √10

Distance between JM and KL = √(3-⁻2)² + (1-0)² = √25 + 1 = √26

Scale is 10

Actual distance = 10*(√10 + √26) = 82.6 = 83 units


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Look Down Below For question:
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