(x^3+x^2-9x-6)÷(x^2-9) using long division? How would I solve?
1 answer:
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9514 1404 393
Answer:
57
Step-by-step explanation:
Apparently, you want to simplify ...
so the denominator is rational. It looks like the form you want is ...
And you want to know the sum A+B+C+D+E+F.
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We can start by multiplying numerator and denominator by a conjugate of the denominator. Then we can multiply numerator and denominator by a conjugate of the resulting denominator.
Comparing this to the desired form we have ...
A = 4, B = 3, C = -1, D = -1, E = 42, F = 10
Then the sum is ...
A +B +C +D +E +F = 4 + 3 -1 -1 +42 +10 = 59 -2 = 57
The sum of interest is 57.
Answer:
- as written, -2
- with denominator parentheses, 0
- with f(x)=ln(x) and denominator parentheses, -1/2
Step-by-step explanation:
The problem as stated asks for the limit as x approaches 2 of (0/x) -2.
As written, the limit is (0/2) -2 = -2.
<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/x -2 is defined as -2 everywhere except x=0. So, the value at x=2 is 0/2 -2 = -2.
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If you mean (f(2) -f(x))/(x -2), that limit is the limit of 0/(x-2) = 0 as x approaches 2.
<u>Explanation</u>: f(x) is a constant, so the numerator is 0. The ratio 0/(x-2) is zero everywhere except at x=2. The left limit and right limit are both 0 as x approaches 2. Since these limits agree, the limit is said to be 0.
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If you mean f(x) = ln(x) and you want the limit of (f(2) -f(x))/(x -2), that value will be -1/2.
<u>Explanation</u>: The value of the ratio is 0/0 at x=2, so we can find the limit using L'Hôpital's rule. Differentiating numerator and denominator, we have ...
lim = (-1/x)/(1)
The value is -1/2 at x=2.
