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Furkat [3]
3 years ago
13

The chance of winning the race of the horse A is 1/15 and that of horse B is 1/6. What is

Mathematics
1 answer:
irina1246 [14]3 years ago
8 0

Answer:

7/30

Step-by-step explanation:

P = 1/15 + 1/6 = (2+5)/30 = 7/30

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Michael works 35 hours per week and his weekly wage is $756. Find his hourly rate
Leona [35]
Whats the problem?
756/35=21,6
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3 years ago
The recipe for beef stew calls for 1/4 teaspoon of pepper for every 3 potatoes. If 9 potatoes are used, how much pepper is neede
Debora [2.8K]

Answer:

3/4 teaspoons of pepper

Step-by-step explanation:

1/4 teaspoons : 3 potatoes = x teaspoons : 9 potatoes

(1/4)/3 = x/9

3x = 9 * 1/4

x = 3 * 1/4

x = 3/4

Answer: 3/4 teaspoons of pepper

5 0
3 years ago
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Find the inverse: f(x)= x+2/3
Kobotan [32]
I’m not sure if this is right but f(x) = 1/x + 3/2 ?
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2 years ago
15 points Math problem
mote1985 [20]

Answer:

increased=150%=0.75

original price =100%

100%*0.75/150

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4 0
3 years ago
A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable
nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0
3 years ago
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