X(A')=X(A)+4= -1+4=3
X(B')=X(B)+4= -1+4=3
X(C')=X(C)+4= 3+4=7
4 points to the right
Answer:
hmmmm. probably 2? I think it's two
<u>Part</u><u> </u><u>(</u><u>i</u><u>)</u>
1) AB is perpendicular to BC, ED is perpendicular to CD, BC = CD (given)
2) Angles ABC and CDE are right angles (perpendicular lines form right angles)
3) Angles ABC and CDE are equal (all right angles are equal)
4) Angles ACB and DCE are equal (vertical angles are equal)
5) Triangles ABC and EDC are congruent (ASA)
<u>Part</u><u> </u><u>(</u><u>ii</u><u>)</u>
6) AB = DE (corresponding parts of congruent triangles are equal)
You'll have to c<span>ompass tip on A and draw a small ark with pencil approximately in the middle above AB line, now compass tip to point B and cross the ark you made previously.
Do the same on the opposite side without making any change to the compass
Join the lines where crosses of arks on the both side meet and then ,it's done.</span>
Answer:
g = number of girls;
b= number of boys
we know that: g= 6+2b
and that: g+b= 156 kids in total
so we may write g+b=(6+2b)+b=6+3b
but g+b= 156
so 6+3b = 156 => 3b= 156-6=150 => b=150/3=50 => b = 50 (number of boys)
g= 6+2b= 6+2 x 50= 106 => g =106 (number of girls)
Step-by-step explanation:
