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mina [271]
3 years ago
11

A bookcase has a mass of 30 kilograms. A book in the bookcase has a mass of 400 grams. How many books of the same mass would it

take to equal the mass of the bookcase? A. 75 books B. 120 books C. 750 books D. 1,200 books
Mathematics
1 answer:
atroni [7]3 years ago
6 0

Answer: OPTION A

Step-by-step explanation:

You can convert  30 kilograms to grams (1\ kilogram= 1,000\ grams), then:

(30\ kilograms)(\frac{1,000\ grams}{1\ kilogram})=30,000\ grams

Then, if a book in the bookcase has a mass of 400 grams and you need to find the number of books of the same mass that would take to equal the mass of the bookcase, you can divide the weight of the bookcase (in grams) by the weigth of one of these books.

Therefore:

books=\frac{30,000\ grams}{400\ grams}\\\\books=75

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214°

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Answer:

1.  2 \times 10^{- 4} = 2 \div 10^{4}

2. (- 10)^{2} = 100 and - 10^{2} = - 100

3. (a.b.c. ........)^{n} = a^{n}.b^{n}.c^{n}. ..........

Example:  (30)^{4} = (2 \times 3 \times 5)^{4} = 2^{4} \times  3^{4} \times 5^{4}

Step-by-step explanation:

1. We have 2 \times 10^{- 4}, and we have to prove that this term is equivalent to 2 \div 10^{4}.

Now, 2 \times 10^{- 4}

= 2 \times \frac{1}{10^{4} }  

{Since we know the property of exponent as a^{- b} = \frac{1}{a^{b} } }

= \frac{2}{10^{4} }

= 2 \div 10^{4}

2. (- 10)^{2} = (- 10) \times (- 10) = 100 and  

- 10^{2} = - [(10) \times (10)] = - 100

3. The power of products property gives

(a.b.c. ........)^{n} = a^{n}.b^{n}.c^{n}. .......... ........ (1)

For example, we can write, (30)^{4} = (2 \times 3 \times 5)^{4} = 2^{4} \times  3^{4} \times 5^{4} = 810000

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