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2 years ago

What is an equation of the line that passes through the points (-7,-6)and(-1,0)

Mathematics

1 answer:

Bogdan [553]2 years ago

3 0

Answer:

y=x+1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(0-(-6))/(-1-(-7))

m=(0+6)/(-1+7)=6/6=1

y-y1=m(x-x1)

y-(-6)=1(x-(-7))

y+6=x+7

y=x+7-6

y=x+1

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EastWind [94]

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3 years ago

The graph of y = |x − 3| + 2 is reflected across the y-axis. What is an equation of the reflected graph?

pychu [463]

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Step-by-step explanation:

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3 years ago

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2 years ago

Alisiya [41]

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Step-by-step explanation:

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3 years ago

the center of a circle is on the line y=2x and the line x=1 is tangent to the circle at (1,6).find the center and the radius

Julli [10]

The radius and the center of the circle are 4 units and (1,2), respectively

<h3>How to determine the center and the radius?</h3>

The center of the circle is on

y = 2x and x = 1

Substitute x = 1 in y = 2x

y = 2 * 1

Evaluate

y = 2

This means that the center is

Center = (1, 2)

Also, we have the point of tangency to be:

(x, y) = (1, 6)

This point and the center have the same x-coordinate.

So, the distance between this point and the center is

d = 6 - 2

d = 4

This represents the radius

Hence, the radius and the center of the circle are 4 units and (1,2), respectively