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2 years ago

What is an equation of the line that passes through the points (-7,-6)and(-1,0)

Mathematics

1 answer:

Bogdan [553]2 years ago

3 0

Answer:

y=x+1

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(0-(-6))/(-1-(-7))

m=(0+6)/(-1+7)=6/6=1

y-y1=m(x-x1)

y-(-6)=1(x-(-7))

y+6=x+7

y=x+7-6

y=x+1

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the exit to garrett's house is after exit 51 but before exit 62. the number on the exit sing is not a prime nunber. the number i

Alex Ar [27]

52
- is prime? No
- is multiple of 3? No
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53
- is prime? Yes
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54
- is prime? No
- is multiple of 3? Yes
- is multiple of 4? No
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55
- is prime? No
- is multiple of 3? No
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56
- is prime? No
- is multiple of 3? No
continue

57
- is prime? No
- is multiple of 3? Yes
- is multiple of 4? No
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58
- is prime? No
- is multiple of 3? No
continue

59
- is prime? Yes
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60
- is prime? No
- is multiple of 3? Yes
- is multiple of 4? Yes

Therefore 60 is the answer, as it fits all the conditions

Simple trial and error.

5 0

3 years ago

Read 2 more answers

Help please hllooooo

siniylev [52]

9514 1404 393

Answer:

$81

Step-by-step explanation:

The garden is 4 yards = 12 feet by 3 yards = 9 feet. The area of it is the product of these dimensions, ...

(12 ft)(9 ft) = 108 ft²

The cost of fertilizer for that area will be ...

($0.75/ft²)(108 ft²) = $81.00

They will spend $81.00 to fertilize the garden.

8 0

3 years ago

Rewrite the function y= x^2 + 14x + 4 in vertex form

Step2247 [10]

Vertex form is basically commplete the square
y=a(x-h)^2+k

y=x^2+14x+4
take 1/2 of 14 and square it, (7^2=49)
add that and its negative to right side
y=x^2+14x+49-49+4
factor perfect squaer
y=(x+7)^2-49+4
y=(x+7)^2-45

answer is A

4 0

3 years ago

April worked 1 1/2 times as long on her math project as did Carl. Debbie worked 1 1/4 times as long as Sonia. Richard worked 1 3

vlada-n [284]

Answer:

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

Step-by-step explanation:

Some data's were missing so we have attached the complete information in the attachment.

Given:

Number of Hours Carl worked on Math project = $5\frac{1}{4}\ hrs$

$5\frac{1}{4}\ hrs$ can be Rewritten as $\frac{21}{4}\ hrs$

Number of Hours Carl worked on Math project = $\frac{21}{4}\ hrs$

Number of Hours Sonia worked on Math project = $6\frac{1}{2}\ hrs$

$6\frac{1}{2}\ hrs$ can be rewritten as $\frac{13}{2}\ hrs$

Number of Hours Sonia worked on Math project = $\frac{13}{2}\ hrs$

Number of Hours Tony worked on Math project = $5\frac{2}{3}\ hrs$

$5\frac{2}{3}\ hrs$ can be rewritten as $\frac{17}{3}\ hrs.$

Number of Hours Tony worked on Math project = $\frac{17}{3}\ hrs.$

Now Given:

April worked $1\frac{1}{2}$ times as long on her math project as did Carl.

$1\frac{1}{2}$ can be Rewritten as $\frac{3}{2}$

Number of Hours April worked on math project = $\frac{3}{2}$ $\times$ Number of Hours Carl worked on Math project

Number of Hours April worked on math project = $\frac{3}{2}\times \frac{21}{4} = \frac{63}{8}\ hrs \ \ Or \ \ 7\frac{7}{8} \ hrs$

Also Given:

Debbie worked $1\frac{1}{4}$ times as long as Sonia.

$1\frac{1}{4}$ can be Rewritten as $\frac{5}{4}$ .

Number of Hours Debbie worked on math project = $\frac{5}{4}$ $\times$ Number of Hours Sonia worked on Math project

Number of Hours Debbie worked on math project = $\frac{5}{4}\times \frac{13}{2}= \frac{65}{8}\ hrs \ \ Or \ \ 8\frac{1}{8}\ hrs$

Also Given:

Richard worked $1\frac{3}{8}$ times as long as tony.

$1\frac{3}{8}$ can be Rewritten as $\frac{11}{8}$

Number of Hours Richard worked on math project = $\frac{11}{8}$ $\times$ Number of Hours Tony worked on Math project

Number of Hours Debbie worked on math project = $\frac{11}{8}\times \frac{17}{3}= \frac{187}{24}\ hrs \ \ Or \ \ 7\frac{19}{24}\ hrs$

Hence We will match each student with number of hours she worked.

Student Hours worked

April. $7\frac{7}{8} \ hrs$

Debbie. $8\frac{1}{8}\ hrs$

Richard. $7\frac{19}{24}\ hrs$

5 0

3 years ago

Read 2 more answers

The product of a number t and 6 increased by 1 is equal to 43

Flura [38]

6*7=42 42+1=43 therefore the number you are looking for is 7

5 0

3 years ago