The area of the shaded region = area of semicircle - area of triangle ACB = 11.32 cm².
<h3>What is the Area of a Semi-circle and Triangle?</h3>
Area of a triangle = 1/2(base)(height).
Area of a semi-circle = 1/2(πr²).
m∠ACB is a right triangle based on the central angle theorem. Therefore, ΔACB is a right triangle.
Radius of circle = OC = 4 cm
CB = 4 cm
Diameter AB = 2(4) = 8 cm
Using the Pythagorean theorem, find AC in ΔACB:
AC = √(AB² - CB²)
AC = √(8² - 4²)
AC ≈ 6.9 cm
Area of ΔACB = 1/2(CB)(AC)
Area of ΔACB = 1/2(4)(6.9)
Area of ΔACB ≈ 13.8 cm²
Area of semicircle = 1/2(πr²) = 1/2(π)(4²)
Area of semicircle ≈ 25.12 cm²
Area of the shaded region = area of semicircle - area of triangle ACB = 25.12 - 13.8
Area of the shaded region = 11.32 cm²
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