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Eddi Din [679]
4 years ago
13

Sonia has 120 blocks. She decides to stack up all the blocks so that each row

Mathematics
1 answer:
Darina [25.2K]4 years ago
4 0

Answer:

15

Step-by-step explanation:

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In △ABC, point M is the midpoint of AB , point D∈ AC so that AD:DC=2:5. If AABC=56 yd2, find ABMC, AAMD, and ACMD.
Komok [63]

Since point M is the midpoint of AB, then AM=MB.

Consider the area of the triangles ABC and BMC:

A_{ABC}=\dfrac{1}{2}\cdot AB\cdot h_c=56\ yd^2,

where h_c is the height drawn from the vertex C to the side AB.

So, AB\cdot h_c=112\ yd^2.

Now

A_{BMC}=\dfrac{1}{2}\cdot BM\cdot h_c=\dfrac{1}{2}\cdot \dfrac{AB}{2}\cdot h_c=\dfrac{1}{4}\cdot AB\cdot h_c=\dfrac{1}{4}\cdot 112=28\ yd^2.

Also

A_{AMC}=A_{ABC}-A_{BMC}=56-28=28\ yd^2.

Now consider the area of the triangles AMD and CMD. Let h_M be the height drawn from the point M to the side AC.

A_{AMD}=\dfrac{1}{2}\cdot AD\cdot h_M=\dfrac{1}{2}\cdot \dfrac{2AC}{7}\cdot h_M=\dfrac{2}{7}\cdot \left(\dfrac{1}{2}\cdot AC\cdot h_M\right)=\dfrac{2}{7}\cdot A_{AMC}=\dfrac{2}{7}\cdot 28=8\ yd^2.

Therefore,

A_{MDC}=A_{AMC}-A_{AMD}=28-8=20\ yd^2.

Answer: A_{MBC}=28\ yd^2, A_{AMD}=8\ yd^2, A_{MDC}=20\ yd^2.

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Do you know what colors they had?
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Markup is the percentage that the cost of an item is increased.

For example, if a company bought a pair of headphones that costed $100 and they sold it for $150, the markup was 50%, since half of the original cost was added. if the markup were 100% it would have been sold for $200, since it added 100% of the original.

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Sam needs an average of 65 on his two sentence test he scored 60 on his first test what is the minimum grade he needs on his sec
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The minimum Sam need to get is a 70.

70 + 60 = 130
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