The limit of the function tan 6x/sin 2x as x approaches zero is determined by first substituting x by zero. This is equal to zero over zero which is indeterminate. Using L'hopital's rule, we derive each term in the numerator and denominator separately. This is equal to 6 sec^2 x / 2 cos 2x. when substituted with zero again, the limit is 1/2.
Answer:
The third side is 8
Step-by-step explanation:
Since this is a right triangle we can use the Pythagorean theorem
a^2 + b^2 =c^2 where a and b are the legs and c is the hypotenuse
a^2 + 15^2 = 17^2
a^2 +225 = 289
Subtract 225 from each side
a^2 +225-225=289-225
a^2 = 64
Take the square root of each side
sqrt(a^2) = sqrt(64)
a= 8
U need to do math to do the qusion
To answer this question, we need to pose the problem algebraically as follows:
1. The sum of two numbers is -29:
2. The difference of the two numbers is -13:
Then, we have a linear system of equations, and we can solve it by elimination, substitution, as the most suitable for this case. Then, we have that we can sum both equations and we get:
Thus, we have that the value for x = -21. We can use the first equation to substitute this value of x to find the value for y. Then, we have:
Therefore, the two numbers are -21 and -8.
We can check this as follows:
1. -21 + (-8)= -21 -8 = -29
2.-21 -(-8) = -21 + 8 = -13
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answer -2