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Ivenika [448]
3 years ago
7

This is the question ​

Mathematics
1 answer:
zysi [14]3 years ago
3 0

Answer:(1,1)

Step-by-step explanation:

Its asking where both linear and curve lines are being hit,

(fxg)(0)= 1,1

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Y=x^2-4x-1 in vertex form
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The answer is Y= (x-2)^2-5

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Evaluate the expression for x = 2 and y = 4. Enter your answer in the box.<br><br> 16x0 + 2x2 • y –1
swat32

Given that,

The given expression is : 16x^0+2x^2{\cdot}y^{-1}

To find,

The value of the above expression when x = 2 and y = 4

Solution,

We have,

16x^0+2x^2{\cdot}y^{-1}

Put x = 2 and y = 4 in the above expression.

16x^0+2x^2{\cdot}y^{-1}\\\\=16\times (2)^0+2(2)^2\times (4)^{-1}\\\\=16\times 1+2(2)^2\times\dfrac{1}{4}\\\\=16+2\\\\=18

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Read 2 more answers
What is the simplified form of the following expression? 7(3sqrt2x)-3(3sqrt16x)-3(3sqrt8x)
coldgirl [10]

Assignment: \bold{Simplify \ Equation: \ 7\left(3\sqrt{2}x\right)-3\left(3\sqrt{16}x\right)-3\left(3\sqrt{8}x\right)}

<><><><><><><>

Answer: \boxed{\bold{3\sqrt{2}x-36x}}

<><><><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><><><>

[ Step One ] Remove Parenthesis (a) = a

\bold{7\cdot \:3\sqrt{2}x-3\cdot \:3\sqrt{16}x-3\cdot \:3\sqrt{8}x}

[ Step Two ] Simplify Equations

\bold{7\cdot \:3\sqrt{2}x: \ 21\sqrt{2}x}

\bold{3\cdot \:3\sqrt{16}x: \ 36x}

\bold{3\cdot \:3\sqrt{8}x: \ 18\sqrt{2}x}

[ Step Three ] Rewrite Equation

\bold{21\sqrt{2}x-36x-18\sqrt{2}x}

[ Step Four ] Add Similar Elements

\bold{21\sqrt{2}x-18\sqrt{2}x=3\sqrt{2}x}

[ Step Five ] Rewrite Equation

\bold{3\sqrt{2}x-36x}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

7 0
3 years ago
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