Solve 2 X = 6. x = Help would be greatly appreciated

Follow the directions on the attached picture. Show work step by step

Sedaia [141]

Answer:

-4x+8-15/x+2

Step-by-step explanation:

divide

-4x+8x+1/x+2

divide that

-4x+8+-15/x+2

simplify

-4x+8-15/x+2

4 0

3 years ago

I need help getting the answer for the 1st question

Karo-lina-s [1.5K]

If we have two similar triangles:
Triangle 1 (base 1 , height1).
Triangle 2 (base 2, height 2)
Then:

base 1 /height 1=base 2 /height 2

Data:
base 1=0.2 m
height 1= 1 m
base 2= 8 m
height 2=x

We calculate the height of the tower:
base 1 /height 1=base 2 /height 2
0.2 m / 1m=8 m / x
x=(8 m * 1 m) / 0.2 m
x=8 m²/0.2 m
x=40 m

Answer. the heigth of the tower will 40 m

3 0

3 years ago

Please help me! Solve for x : show your steps! 2(x +8) = 4(x+2)

Tju [1.3M]

Answer:

4

Step-by-step explanation:

First, use the distributive property: 2x+16=4x+8

Second, move +8 to the other side(and turn it negative): 2x+8= 4x

Do the same for +2x: 8=2x

divide both sides by 2: 4=x

8 0

3 years ago

What is the area of the paper used to wrap a can of soup if the can is 11 cm tall and has a diameter of 7.5 cm. Show all formula

Dimas [21]

Notice that a can is a cylinder, which is basically two circles and one rectangle. Now, the question wants area of this rectangle.

You know the width of the rectangle (or the paper), which is 11cm. How do you find the length then?

Notice that the length of the rectangle is also the circumference of the circles. From here, use C = πd where C is circumference and d is diameter. The d is given, which is 7.5 cm. Depending on the question, π can be 3.14, 22/7 or the actual pi.

multiply π and 7.5cm and you get the circumference. Multiply this to 11cm and you get area of the rectangle.

6 0

3 years ago

If k stands for an integer, then is it possible for k2 + k to stand for an odd integer? Be prepared to justify your answer.

BartSMP [9]

Answer:

k^2 + k never stands for an odd integer

Step-by-step explanation:

Let us consider either case with which k stands for an odd or even integer;

Case 1: k is an odd integer

For integer a, k = 2a + 1

So, k + 1 = 2a + 2 = 2( a + 1 ) = 2b for integer b

k^2 + k = k ( k + 1 ) = k ( 2b ) = 2kb = 2c for integer c,

Therefore, if k is an odd integer, then k^2 + k is an even integer ;

Case 2: k is an even integer

For an integer a, k = 2a

So, k + 1 = 2a + 1

k^2 + k = k( k+1 ) = 2a( 2a + 1 ) , multiple of 2

Therefore, if k is an even integer, then k^2 + k is an even integer;

This would make k^2 + k never stand for an odd integer

5 0

3 years ago