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Monica [59]
3 years ago
5

Write exponential equation for geometric sequence where t(1)=140 and t(2)=98

Mathematics
1 answer:
ser-zykov [4K]3 years ago
4 0

Step-by-step explanation:

common ratio r = 98/140

first term a = 140

geometric sequence formula is an = ar^(n-1)

an = 98^(n-1)

where n is the number of terms in the sequence

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Step-by-step explanation:

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3 years ago
What is the sum of the geometric sequence -3, 18, -108, ... if there are 8 terms
creativ13 [48]

Answer:

Step-by-step explanation:

common ratio=18/-3=-108/18=-6, a=-3

sn=a(r^n-1)(r-1)

sn=-3((-6)^n-1)(-6-1)

sn=-3(-6)^8-1)/(-7)

s8=-3(1679615)/(-7)

s8=719836

6 0
3 years ago
Factor 15z^2+17z-18 please show work
siniylev [52]

There is no common factor between 15, 17 and 18 because 17 is prime.  

15z² +17z - 18 =  

d = 17² - 4.15.-18  

d = 289 + 1080  

d = 1369  

z = (-17 +/- \/1369) : 2 * 15  

z = (-17 + 37) : 30  

z' = 20 : 30 = 2/3  

z" = (-17 - 37) : 30  

z" = -54 : 30 = -1.8  

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7 0
3 years ago
Point Q' is the image of Q(5, -3) after a translation down 2 units and right 4 units. What are the coordinates of Q'?
ra1l [238]

Answer:

A. (9,-5)

Step-by-step explanation:

Translation down is -2 to the y coordinate, which is (5,-5). Then you translate it right 4 units, which is +4 to the x coordinate, so the final coordinate is (9,-5).

5 0
3 years ago
If a4 = 625, what does (a) equal?
Reika [66]

I'm assuming you meant to write a^4 = 625.

If that is the case, then note how 625 = 25^2, and how a^4 is the same as (a^2)^2

So we go from this

a^4 = 625

to this

(a^2)^2 = 25^2

Apply the square root to both sides and you'll end up with: a^2 = 25

From here, apply the square root again to end up with the final answer: a = 5 or a = -5

As a check:

a^4 = (-5)^4 = (-5)*(-5)*(-5)*(-5) = 25*25 = 625

a^4 = (5)^4 = (5)*(5)*(5)*(5) = 25*25 = 625

Both values of 'a' work out

4 0
3 years ago
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