I believe it's 5 spaces for an indent. If that's incorrect plz forgive me lol.
IAM stands for<em> </em>Identity Access Management and includes processes focused on control of user access to critical information.
DIACEP on the other hand stands for DoD Information Assurance Certification and Accreditation Process and it is a process which ensures that companies apply risk management to information systems (IS). According these explanations, the statement that Jim who is IAM in the organization is not required to assist the PM in implementing the DIACAP is false. In contrast, it is required that he works on this process.
Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
Your answer would be:
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