<h3>Given -:</h3>
change in emitter current, ∆l(E) = 4 mA
change in collector current,∆I(C) = 3.5 mA
<h3>To find -:</h3>
value of B
<h3>Solution :-</h3>
∆I(E) = ∆I(C) + ∆l(B), here ∆l(B) is the change in base current.
4 = 3.5 + ∆l(B)
∆I(B) = 0.5 mA
<h3>Now, B = ∆l (C) ÷ ∆l (B)</h3>
B = 3.5 ÷ 0.5
B = 7.0
<h3>so, the value of A = 7.0</h3>
Question 4. Just replace x with 2a.
So f(2a) = 5(2a)^2 + 4(2a)
= 5*4a^2 + 8a
= 20a^2 + 8a
Question 5. Since x = 3, which is more than 1, use the second equation.
f(3) = 3^2 + 1
= 9 + 1
= 10
Answer:
The upper bound is 399.5
Step-by-step explanation:
Let's start by calculating the mean value of the distribution as the addition of all values given divided by 12:
Average = 289.75.
If the standard deviation is 56, then the upper bound in 95% the confidence interval for the mean price of the phones is going to be given by the mean value added to 56 times 1.96 (since 95% of the population is withing 1.96 times the standard deviation)
That is: 289.75 + 56 * 1.96 = 399.51
which rounded to one decimal place gives: 399.5
Answer:
Step-by-step explanation:
a. 5 3/6 - 1 2/6 = 4 1/6
b. 8 9/12 - 5 10/12
7 21/12 - 5 10/12= 2 11/12
Answer:
Matty is a bit of a weirdo you know what i mean
Step-by-step explanation:
