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oee [108]
3 years ago
15

by what percent will a fraction change if its numerator is decreased by 75% and denominator is decreased by 50%

Mathematics
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

50%

Step-by-step explanation:

first the numerator is decreased by 75% so its 0.25. the denominator is decreased by 50% so its 0.5. Then, we will divide 0.25 and 0.5 which equals 0.5. to find %, do 0.5*100 which equals 50%

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If terrance ran 12mph and jesse ran 8mph how long will it take them to run 50 miles
Sholpan [36]

Answer:

Terrance would take 4.2666 hours, Jesse would take 6.25 hours

Step-by-step explanation:

1h/12m per hour x 50m/1h is also 50m/12m per hour = 4.266 hours (round number)

1h/8m per hour is also 50m/8m per hour = 6.25 hours (round number)

6 0
3 years ago
45 + 15(n − 1) for n = 6
blondinia [14]

Answer:

120

Step-by-step explanation:

45 + 15 (6 -1)

45 + 15 (5)

45 + 75

120

3 0
3 years ago
If x - 3 Is a factor P(x) = x ^ 3 - 7x ^ 2 + 15x - 9, which of the following represents the complete factorization for P(x) ?
sattari [20]

the answer is c, i just got this question

3 0
2 years ago
Which is an equation of the line that passes through the point
Allisa [31]

Answer:

y = \frac{1}{2} x+3

Step-by-step explanation:

4 0
2 years ago
The maximum afternoon temperature in Granderson is modeled by t=60-30 cos (x<img src="https://tex.z-dn.net/?f=%20%5Cpi%20" id="T
kicyunya [14]
The equation is t=60-30 cos (x \frac{\pi}{6})

the -30 expression, is subtracting, if negative, from the 60
if the cosine returned is negative, you'd end up with a +30,
negative * negative = positive

and then the 30 expression will ADD to the 60 amount
so the temperature "t" is highest, when the 30 expression, is
positive and and it's highest

when does that happen, when cosine is negative and at its highest,
well, cosine range is -1\le cos(\theta ) \le 1
so the lowest value cosine can provide is -1, when is cosine -1?
well, at \pi

so...  let's find a value that makes that expression to cos(\pi)

\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=6&#10;\\\\&#10;thus&#10;\\\\&#10;t=60-30 cos (6 \frac{\pi}{6})\implies t=60-30 cos (\pi )&#10;\\\\&#10;t=60-30[-1]\implies t=60+30\implies t=90

----------------------------------------------------------------------------------------
so...for August, that'll mean


\bf t=60-30 cos (x \frac{\pi}{6}) \qquad x=7&#10;\\\\&#10;t=60-30 cos (\frac{7\pi}{6})\implies t=60-30\left( -\cfrac{\sqrt{3}}{2} \right)&#10;\\\\&#10;t=60+(15\cdot \sqrt{3})\implies t\approx85.98^o


4 0
3 years ago
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