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Maslowich
3 years ago
9

Gina is comparing the membership fees for two museums. The art museum charges a one-time fee of $7.25 plus $3.50 per month. - Th

e science museum charges a one-time fee of $10.50 plus $4.50 per month. How much does she save after m months by joining the art museum instead of the science museum? (Hint: write the expressions for the art museum and the science museum FIRST and then find the difference)​
Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:

<em>here two links for your answer. https://quizlet.com/325167814/financial-math-flash-cards/ https://quizlet.com/475135130/financial-math-e2020-flash-cards $2.5</em>

<em></em>

<em>Step-by-step explanation:</em>

<em></em>

<em>The art museum charges a one-time fee of $8.25 plus $2.25 per month.</em>

<em></em>

<em>So, the cost function for membership for x months in the art museum f(x) = 8.25 + 2.25x .............. (1)</em>

<em></em>

<em>Again, the science museum charges a one-time fee of $10.75 plus $3.5 per month.</em>

<em></em>

<em>Hence, the cost function for membership for x months in the science museum g(x) = 10.75 + 3.5x ........... (2)</em>

<em></em>

<em>So, from both the equations it is clear that for only joining the monthly charges are zero.</em>

<em></em>

<em>So, f(0) = 8.25 and g(0) = 10.75.</em>

<em></em>

<em>Therefore, Barrett will save by joining the art museum instead of the science museum by $(10.75 - 8.25) = $2.5. (Answer)</em>

<em></em>

Step-by-step explanation:

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Two vertical poles of heights 60 ft and 80 ft stand on level ground, with their bases 100 ft apart. A cable that is stretched fr
Andreyy89

Answer:

Step-by-step explanation:

Given

height of two Poles are 60 and 80 ft

Distance between them is 100 ft

Let x be the distance of Pole of ht 80 ft from Point of stretch

thus length of rope is given by

L=L_1+L_2

L_1=\sqrt{80^2+x^2}

L_2=\sqrt{60^2+(100-x)^2}

L=\sqrt{80^2+x^2}+\sqrt{60^2+(100-x)^2}

differentiate w.r.t x we get

\frac{\mathrm{d} L}{\mathrm{d} x}=\frac{2x}{2\sqrt{80^2+x^2}}-\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}

Put \frac{\mathrm{d} L}{\mathrm{d} x}=0 to get minimum value

\frac{2x}{2\sqrt{80^2+x^2}}=\frac{2\left ( 100-x\right )}{\sqrt{60^2+\left ( 100-2x\right )^2}}

squaring

x^2\left ( (100-x)^2+60^2\right )=(100-x)^2(80^2+x^2)

Rearranging

28x^2-1800x+640000=0

x=\frac{400}{7}

thus L_1=98.312 ft

L_2=73.73 ft

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7 0
3 years ago
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Ostrovityanka [42]
The area is 448.5
(13 × 29) + (11 × 13)1/2
5 0
3 years ago
If the length of the shorter leg of a right triangle is 5 cm and the length of the hypotenuse is 8 cm, find the length of the lo
Brilliant_brown [7]

Answer:

The length of the longer leg is 6.24 cm.

Step-by-step explanation:

Here, the length of the hypotenuse  = 8 cm

The length of shorten leg ( Base) = 5 cm

Let us assume the length of longer leg (Perpendicular)   = k cm

Now, as the given triangle is a right angled triangle.

So, by the PYTHAGORAS THEOREM:

( Base)^2 + ( Perpendicular)^2  = ( Hypotenuse)^2\\\implies (5)^2  + (k)^2  = (8)^2\\\implies k^2  = 64 - 25  =  39\\\implies k^2  = 39\\k = \sqrt{(39)}  = \pm (6.24)

Now,as k is the length of the side, so it cannot be negative.

⇒   k  =  6.24 cm

Hence, the length of the longer leg is 6.24 cm.

6 0
3 years ago
Find two numbers such that the sum of the first and three times the second is 5 and the sum of the second and two times the firs
Sav [38]

Answer:

first number= 19/5

second number= 2/5

Step-by-step explanation:

first number= a

second number= b

a+3b=5   equation 1

b+2a=8  equation 2

using equation 2 we have

b=8-2a

using equation 1 we have

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24-5=6a-a

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a=19/5 = first number

so using b=8-2a

we have

b=8-2(19/5)

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b=2/5 = second number

4 0
4 years ago
Just givin out to the people
son4ous [18]

Answer: Thanks

Step-by-step explanation:

8 0
3 years ago
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