Answer:
(y+1) = -3(x-2)
Step-by-step explanation:
y-y₁=m(x-x₁)
notice the negatives in the formula.
this changes coordinates. the positives to negative and negatives to positives
This is an exponential function since the x is in the exponent's place instead of in the place of a "regular" variable. The first statement is true.
The initial value of this particular function is 3 (the other number is the multiplier), so choice 2 is NOT true.
The function increases by its multiplier, which is 2.5, so statement 3 is true.
The equation allows us to enter any x value we want to determine the y, so the domain is in fact all real numbers. So, this statement is also true.
If you were to graph this on a calculator, you would see that the range, the "allowed" y values for our function, do not touch or ever drop below the x-axis. That means that the range is all numbers greater than 0. So that statement is false. No matter what value we pick for x, we will NEVER get back a negative y value or that y = 0. For example, if x = 0, y = 3; if x = -5, y = .03; if x = -10, y = .0003; if x = 5, y = 292.97; if x = -100,
. Y will never be equal to 0 or less than 0.
Its like that because the judges deduct points from that score. They can be major or minor deductions.
Answer:
-3·m^12·n^6
Step-by-step explanation:
We assume you intend ...
(-24·m^5·n^4)/(8·m^-7·n^-2)
= (-24/8)·m^(5-(-7))·n^(4-(-2))
= -3·m^12·n^6
_____
If you really intend what you have written, then it simplifies to ...
(-24·m^5·n^4/8)·m^-7·n^-2 . . . . . note that all factors involving m and n are in the numerator
= (-24/8)·m^(5-7)·n^(4-2) = -3n^2/m^2
19.6 is the answer to your question