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3 years ago

3(x+2)=9(6-x) Answer please and show your work :D

Mathematics

1 answer:

Nookie1986 [14]3 years ago

6 0

Answer: x=4

Step-by-step explanation: 3x+6= 54-9x

6= 54 -12x

-48=-12x

x=4

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What is the value of X ?

Zielflug [23.3K]

Answer:

x = 12

Step-by-step explanation:

their the same length so plug em equal to each other

x+5 = 2x-7

add 7 to both side to get x+12 = 2x

subtract x from both side to get x = 12

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3 years ago

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Aliun [14]

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2 years ago

I need help with the problem

maxonik [38]

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Step-by-step explanation:

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2 years ago

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3 years ago

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Example 2: Combining Use of the Multiplication and Addition Rules

bulgar [2K]

Answer:

The probability of getting 6's on both cubes is $\frac{1}{36}$ .

The probability that the total score is at least 11 is $\frac{1}{12}$ .

Step-by-step explanation:

Consider the provided information.

A red cube has faces labeled 1 through 6, and a blue cube has faces labeled in the same way.

Part (A) Both cubes show 6’s.

Probability of getting 6 on red cube is $\frac{1}{6}$

Probability of getting 6 on blue cube is $\frac{1}{6}$

Thus, the probability of getting 6's on both cubes is:

$P(\text{Both 6's})=\frac{1}{6}\times\frac{1}{6}=\frac{1}{36}$

Hence, the probability of getting 6's on both cubes is $\frac{1}{36}$ .

Part (B) The total score is at least 11.

The possible number of outcomes in which total score is at least 11 is:

Red shows 6 and Blue shows 5.

Blue shows 6 and Red shows 5.

Blue shows 6 and Red shows 6.

Thus, the probability of total score is at least 11.

$P(\text{Total is at least 11})=\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}+\frac{1}{6}\times\frac{1}{6}\\P(\text{Total is at least 11})=\frac{1}{12}$

Hence, the probability that the total score is at least 11 is $\frac{1}{12}$ .

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3 years ago