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3 years ago

7

HELP PLEASE I WILL MARK YOU BRAINIEST

1 answer:

kotegsom [21]3 years ago

8 0

Step-by-step explanation:

In total there is 6 cups of soup.

So lets put that in /8 form

48/8 and do the same to the other 27/8

So when you see it takes 27/8 for one you know she can only do one full serving.

21/8 is what's left

So 2 5/8 is left

She is 6/8 off of one more serving

I'm sorry this is all I can do. I hope you can use this info to answer

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The figure shows a large triangle divided into two smaller triangles what is the value of x in the figure

nata0808 [166]

Answer:

40

Step-by-step explanation:

Find the other missing angle, which is supplementary to 100 first.

Supplementary angels are a sum of 180

The missing angle is 180-100 = 80

Now use that to find missing angle x

All angles in the triangle have a sum of 180

180 = 60+80+x

180-60-80=x

40 = x

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3 years ago

Dahasolnce [82]

Answer:

a) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$ , b) $x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$ , $x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

Step-by-step explanation:

a) The equation must be rearranged into a form with one fundamental trigonometric function first:

$\sqrt{3}\cdot \csc x - 2 = 0$

$\sqrt{3} \cdot \left(\frac{1}{\sin x} \right) - 2 = 0$

$\sqrt{3} - 2\cdot \sin x = 0$

$\sin x = \frac{\sqrt{3}}{2}$

$x = \sin^{-1} \frac{\sqrt{3}}{2}$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{6}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

b) The equation must be simplified first:

$\cos x + 1 = - \cos x$

$2\cdot \cos x = -1$

$\cos x = -\frac{1}{2}$

$x = \cos^{-1} \left(-\frac{1}{2} \right)$

Value of x is contained in the following sets of solutions:

$x_{1} = \frac{\pi}{3}\pm 2\pi \cdot i$ , $\forall i \in \mathbb{N}_{O}$

$x_{2} = \frac{5\pi}{3}\pm 2\pi\cdot i$ , $\forall i \in \mathbb{N}_{O}$

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3 years ago

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anzhelika [568]

Answer:

5a(6 $b^{4}$ - $a^{5}$ )

Step-by-step explanation:

Given

30a $b^{4}$ - 5 $a^{6}$ ← factor out 5a from each term

= 5a(6 $b^{4}$ - $a^{5}$ ) ← in factored form

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ale4655 [162]

Answer:

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Step-by-step explanation:

85/5

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Step-by-step explanation:

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