Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
Answer:
Option C.
Step-by-step explanation:
Given information: RSTU is a parallelogram, Digonals RT and SU intersect each other at point V, UV=(x-3) and VS=(3x-13).
According to the properties of a parallelogram, the diagonals of a parallelogram bisect each other.
Using the properties of parallelogram we can say that point V divides the diagonal SU in two equal parts, UV and VS.
Subtract x from both sides.
Add 13 on both sides.
Divide both sides by 2.
Therefore, the correct option is C.
Answer:
Step-by-step explanation:
the lines weren't really clear so sorry if its a bit messy
the answer is x is equal to -4
x=-4
Let us for a few seconds nevermind there's a circle at all, so we only really have a triangle by itself.
now, EF = 18, wait a second! EF is the base of the triangle, and h = 10.725, wait a minute!! "h" is the height of the triangle.
so, what's the area of a triangle whose base is 18 and has a height of 10.725? yeap, we knew you'd know that one.
what's the length of the arcEF? well, we know the central angle of ∡FOE is 80°, well, arc's get their angle measurement from the central angle they're in, so if ∡FOE is 80°, so is arcEF then.
