First, find the nth term
To do this, find the term to term difference...
A
-7 and 3 = 10
3 and 13 = 10
13 and 23 = 10
As the difference is 10, we now write out the 10 times table
10, 20, 30, 40
The next step is to work out how to get from the sequence to the 10x table
B
-7 - 10 = -17
3 - 20 = -17
13 - 30 = -17
23 - 40 = -17
Now use the answer from each section in the general formula
x = An + B
This could also be written as ?n + ?
Using our numbers, this becomes 10n - 17
Now use the formula to work out the 110th term
(10 x 110) - 17
1100 - 17 = 1083
Answer:
22.38 g of silicone-32 will be present in 300 years.
Step-by-step explanation:
A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by
where,
= quantity of the substance remaining
= initial quantity of the substance
= time elapsed
= half life of the substance
From the information given we know:
- The initial quantity of silicone-32 is 30 g.
- The time elapsed is 300 years.
- The half life of silicone-32 is 710 years.
So, to find the quantity of silicone-32 remaining we apply the above equation
22.38 g of silicone-32 will be present in 300 years.
Answer: 6f (3+5x)
Step-by-step explanation:
18f + 30fx by its gcf