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stiks02 [169]
3 years ago
11

Whats the answer please​

Mathematics
1 answer:
slava [35]3 years ago
7 0

Answer:

A) 4

Step-by-step explanation:

The reason why the answer is four is because,

130 = 33x - 2 (These two angles are alternate exterior angles)

=> 130 + 2 = 33x

=> 132 = 33x

=> 132/33 = x

=> 4 = x

If my answer helped, please mark me as the brainliest

Thank you!

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A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one
TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are \binom44\binom{48}1=48 possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by \binom{13}1=13. So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing \binom41\binom{48}4=778,320 possible hands. Exactly 2 aces are drawn in \binom42\binom{48}3=103,776 hands. And so on. This gives a total of

\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656

possible hands containing at least 1 ace, and hence B occurs with probability

\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. P(A\cap B)=P(A)P(B). This happens if

  • the hand has 4 aces and 1 non-ace, or
  • the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So A\cap B consists of 96 possible hands, which occurs with probability

\dfrac{96}{\binom{52}5}\approx0.0000369

and so the events A and B are NOT independent.

4 0
3 years ago
The combined weight of the people in the elevator is 49% of the 3,025 pound capacity. Which would be The best way to estimate th
qaws [65]

Answer:

Around 1,500 pounds

Step-by-step explanation:

Because you said "estimate," I will be estimating this.

49% rounds up to 50%

3,025 rounds down to 3,000

50% of 3,000 is 1,500 pounds.

8 0
3 years ago
I'm gonna go in order now, I'll mark you the brainiest and give you the more points
velikii [3]
Skew lines are lines that are not pararell or perpendicular.

The only lines that fit this explanation are AE and GF

Hope this helps!
7 0
3 years ago
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500 portions of strawberries have been ordered for the tournament, but because of bad weather only
Citrus2011 [14]

We conclude that 375 portions can be sold.

<h3>How many portions can be sold?</h3>

We know that 500 portions have been ordered, but only 5/6 of that was delivered, so the number of delivered portions is:

p = (5/6)*500 = 416.6

Which we can round to the next whole number, 417.

Now we know that 10% of these are given to the players and staff, then the number of portions that can be sold is the 90% of 417, which is:

N = 417*(90%/100%) = 417*0.9 = 375

We conclude that 375 portions can be sold.

If you want to learn more about percentages:

brainly.com/question/843074

#SPJ1

8 0
1 year ago
Can someone pls answer all 6 questions pls? Pretty pls, except 1 and 5 thank you so much!!!
Maksim231197 [3]
2) C
3) B
4) C
6) I'm pretty sure its D but it could be C
7 0
3 years ago
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