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snow_lady [41]
3 years ago
7

Please help I really don’t understand this

Mathematics
1 answer:
kozerog [31]3 years ago
8 0

Answer:

for number 1 set them equal to each other so like 6x-44=88 and then solve for x and do the same thing for the second one

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tony bought a video game on sale for $7 off the original price of $45.99. What percent was the video game marked down?
exis [7]

Answer: 52 $

Step-by-step explanation:

5 0
4 years ago
Two numbers have a sum of 1,212 and a difference of 518. What are the two numbers?
sashaice [31]

Answer:

347 and 865

Step-by-step explanation:

Let the two number be x and y

Therefore, from the given information:

x + y = 1212

x - y = 518

Rewrite both equations to make x the subject:

x = 1212 - y

x = 518 + y

Equate equations and solve for y:

1212 - y = 518 + y

     694 = 2y

         y = 347

Substitute found value of y into one of the equations and solve for x:

x = 518 + 347

x = 865

Therefore, the two numbers are 347 and 865

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3 years ago
Which one is correct? How’d you do it? Card 4
alexandr402 [8]

Times em all I say or at least that’s what I would do sorry if I didn’t help

5 0
3 years ago
What is 10.5 in Scientific Notation
erastova [34]
<span>10.5 in Scientific Notation
= 1.05 x 10^-1
------------</span>
4 0
3 years ago
Read 2 more answers
There are 348 identical plastic chips numbered 1 through 348 in a box. What is the probability of reaching into the box and rand
hoa [83]
<h2>P(E) = \dfrac{53}{87} or, 0.6092</h2>

Step-by-step explanation:

Given,

There are 348 identical plastic chips numbered 1 through 348 in a box.

To find, the probability of reaching into the box and randomly drawing a chip number which is smaller than 213 = ?

Total number of possible outcomes = 348

Let E be the event of getting randomly drawing a chip number that is smaller than 213.

Favourable outcomes are:

1, 2, 3, .............., 212

Number of favourable outcomes = 212

∴ Probability =

P(E) =

= \dfrac{53}{87} or, 0.6092

Thus, P(E) = \dfrac{53}{87} or, 0.6092

4 0
4 years ago
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