Answer:
Probability (bid accepted) = 0.48
Step-by-step explanation:
Probability density is given byF(y)= 1/(b-a)
a=9500
b= 14700
F(y)= 1/(14700-9500) =1/5200=0.00019
Probability (bid accepted)= (12000-9500)÷1/5200
P( bid accepted) = 2500×0.00019=0.475 approximately 0.48
Answer:
Seth saved $90.
Step-by-step explanation:
1.Find out how much would be spent without buying the movie pass.
Multiply the amount of money that one would spend for each movie, by the number of movies one saw.
8 * 30 = 240
2.Find out the amount that was actually spent
Multiply the amount that was actually spent on each movie, by the number of movies that were seen. Then add the additional cost of the pass.
(4 * 30) + 30
= 120 + 30
= 150
3. Find the difference between the two values.
Subtract the amount that one was supposed to spend by the amount one did spend.
240 - 150
= 90
Answer:
a) 13 m/s
b) (15 + h) m/s
c) 15 m/s
Step-by-step explanation:
if the location is
y=x²+3*x
then the average velocity from 3 to 7 is
Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s
then the average velocity from x=6 to to x=6+h
Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s
the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then
when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s
then v= 15 m/s
also can be found taking the derivative of y in x=6
v=dy/dx=2*x+3
for x=6
v=dy/dx=2*6+3 = 12+3=15 m/s
The speed of the current is 40.34 mph approximately.
<u>SOLUTION:
</u>
Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.
We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.
And, we know that, 
We are given that, time taken for both are same. So 
Answer:
square inches.
Step-by-step explanation:
<h3>Area of the Inscribed Hexagon</h3>
Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be 
inches (same as the length of each side of the regular hexagon.)
Refer to the second attachment for one of these equilateral triangles.
Let segment 
be a height on side 
. Since this triangle is equilateral, the size of each internal angle will be 
. The length of segment
.
The area (in square inches) of this equilateral triangle will be:
.
Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:
.
<h3>Area of of the circle that is not covered</h3>
Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is inches, the radius of this circle will also be inches.
The area (in square inches) of a circle of radius inches is:
.
The area (in square inches) of the circle that the hexagon did not cover would be:
.
