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trasher [3.6K]
4 years ago
5

Find equations of the line that is parallel to the z-axis and passes through the midpoint between the two points (0, −3, 7) and

(−2, 4, 1).
Mathematics
1 answer:
tia_tia [17]4 years ago
7 0

Answer:

\vec{r}(t)=\left

In parametric form:

x=-1, y=\displaystyle\frac{1}{2}, z=4+t

Step-by-step explanation:

We first find the mid point:

\displaystyle\left(\frac{0+(-2)}{2},\frac{-3+4}{2},\frac{7+1}{2}\right)=\left(-1,\frac{1}{2},4\right)

Then, a vector parallel to the z-axis is:

\vec{v}=\left< 0,0,1 \right>

Then remember the equation of  a line passing through point (x_o,y_o,z_o) and parallel to the vector \vec{v}=\left is:

\vec{r}(t)=\left+t\left

So, in this problem we get:

\vec{r}(t)=\left+t\left

After combining the two vectors:

\vec{r}(t)=\left

In parametric form:

x=-1, y=\displaystyle\frac{1}{2}, z=4+t

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I sent help but no one answered :(

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12(t + 2) + 4 ≥ - 8

12t + 24 + 4 ≥ - 8

12t + 28       ≥ - 8

12t               ≥ - 8 - 28

12t               ≥ - 36

t                  ≥ - 36 ÷ 12

t                  ≥ - 3

Solution:

t ≥ -3

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3 years ago
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Step-by-step explanation:

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earnstyle [38]

Answer:

any coordinate outside the parabola is a reasonable answer.

Step-by-step explanation:

test the solution (0, 0) and if if that number is greater than 0 then the rest of the points outside on the inside are.

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3 years ago
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alexandr1967 [171]

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Answer:

  9n^4

Step-by-step explanation:

The divisor and quotient can be interchanged to find the divisor:

  \dfrac{18n^6+27n^5-36n^4}{2n^2+3n-4}=\boxed{\text{Blank 1}}

Such division is carried out by first finding the quotient of the highest-degree terms:

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This value is used to multiply the denominator and subtract that product from the numerator to find the new numerator. The new numerator is zero, so the value that goes in Blank 1 is ...

  9n^4

_____

The attachment shows the long division.

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