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RSB [31]
3 years ago
7

Jesse added two more numbers to his expression, but the sum did not change. What could the two new numbers be? Explain why the n

umbers you chose would not affect the sum of Jesse’s expression.
Mathematics
2 answers:
morpeh [17]3 years ago
8 0
I think the answer is zero
kenny6666 [7]3 years ago
4 0

Answer:

0 and 0

Step-by-step explanation:

The only number that can be applied to the expression without changing the sum is 0, for example 5 + 10 = 15, adding 2 0's will be 0 + 5 + 10 + 0 = 15 :D

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I need help with those questions please help me.
Goshia [24]

Answer:

1 = 21 m

2 = 120 cm

3 = 84 cm

4 = 3 km

5 = 10 m

6 = 55 mm

7 = 60 cm

8 = 500 mm

Step-by-step explanation: you see where it says "perimeter = 3s" right? for each question you have to replace "s" with the number given so for the first one it would be 3 x 7. You had to do the same thing with the others but sometimes we get confused in math :D

8 0
2 years ago
What is 3 divided by 11/12
Lena [83]

Answer:

0.02272

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the length of the curve. R(t) = cos(8t) i + sin(8t) j + 8 ln cos t k, 0 ≤ t ≤ π/4
arsen [322]

we are given

R(t)=cos(8t)i+sin(8t)j+8ln(cos(t))k

now, we can find x , y and z components

x=cos(8t),y=sin(8t),z=8ln(cos(t))

Arc length calculation:

we can use formula

L=\int\limits^a_b {\sqrt{(x')^2+(y')^2+(z')^2} } \, dt

x'=-8sin(8t),y=8cos(8t),z=-8tan(t)

now, we can plug these values

L=\int _0^{\frac{\pi }{4}}\sqrt{(-8sin(8t))^2+(8cos(8t))^2+(-8tan(t))^2} dt

now, we can simplify it

L=\int _0^{\frac{\pi }{4}}\sqrt{64+64tan^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8\sqrt{1+tan^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8\sqrt{sec^2(t)} dt

L=\int _0^{\frac{\pi }{4}}8sec(t) dt

now, we can solve integral

\int \:8\sec \left(t\right)dt

=8\ln \left|\tan \left(t\right)+\sec \left(t\right)\right|

now, we can plug bounds

and we get

=8\ln \left(\sqrt{2}+1\right)-0

so,

L=8\ln \left(1+\sqrt{2}\right)..............Answer

5 0
3 years ago
What is the answer please?
docker41 [41]

Answer: D (bottom option)

Not Congruent

Step-by-step explanation:

Assuming the trapezoids are to scale, they are not the same shape. This means that they could not be congruent even if they were centered on top of each other.

3 0
2 years ago
Point K is rotated 90°. The coordinate of the pre-image point kwas (2-6) and its image K is at the coordinate
Sati [7]
Point K was rotated 90° clockwise.
5 0
3 years ago
Read 2 more answers
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