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posledela
3 years ago
6

What is the growth factor of the following example? Assume time is measured in the units given.

Mathematics
1 answer:
olga55 [171]3 years ago
7 0

Answer:

C. 0.99 per day

Step-by-step explanation:

I calculated it logically

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At the party ⅗ of a pie are eaten.
masya89 [10]

Answer:

1/10 of the pie

Step-by-step explanation:

3 0
3 years ago
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Evaluateeee????????????
andreev551 [17]
The answer is 15. just replace the letters with the numbers they're equal to.
8 0
3 years ago
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what is the experimental probability of the spinner of it landing on blue? if it has green in the upper left corner, blue in the
Sidana [21]
1/4 are you chances in that question
7 0
3 years ago
There are 3 times as many males as females on the maths course at university. What fraction of the course are male?
exis [7]

(1)

If there are three times as many males as females, the ratio of males to females would be 3:1.

To make this more clearer. Suppose you have 100 students. for each 4 students, 3 of them are male and 1 is a female.

We can then say there are 75 males and 25 females.

Expressing this as a ratio(fraction) is easy 3 out of 4 are males and 1 out of 4 are females. So the ratio of males would be;

r(m) =  \frac{3}{4}

(2)

Let x be the number of cola bottles

Let y be the number of smarties

Let z be the number of marshmallows

x=3y (since there are 3 times more x than y)

y=2z (since there are 2 times more y than z)

we know that marshmallows are twice as less as smarties. so for 1 marshmallow you'd have 2 smarties. But we also know that cola bottles should be 2×3=6 since we have 3 times more cola bottles than smarties.

Adding up our total sweets we get;

1+2+6=9

But how many of those are cola bottles? 6!

So the ratio of cola bottles can be expressed as,

r(c) =  \frac{6}{9}  =  \frac{2}{3}

You can simplify the numerator and denominator by 3 to get 2 over 3.

5 0
2 years ago
Each letter of the word "thunderstorm" has been written on a separate slip of paper and put into a box. Find the probability of
xxTIMURxx [149]

SOLUTION

From the question, we want to find the probability of selecting a slip of paper with the letter t on it, then selecting the letter r, with replacement.

This means the probability of selecting t and r.

That is

P(t)\times P(r)

There are 12 letters (total outcomes). And there are 2r and 2t.

So probability becomes

\begin{gathered} \frac{possible\text{ outcome}}{\text{total outcome }} \\ P(t)=\frac{2}{12} \\ P(r)=\frac{2}{12} \\ P(t)\times P(r)=\frac{2}{12}\times\frac{2}{12} \\ =\frac{1}{6}\times\frac{1}{6} \\ =\frac{1}{36} \end{gathered}

Hence the answer is

\frac{1}{36}

7 0
1 year ago
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