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Alenkinab [10]
4 years ago
10

Q(a+y)=67y+93 Solve for y

Mathematics
2 answers:
bekas [8.4K]4 years ago
6 0
Qa + Qy = 67y + 93
Qy - 67y = 93 - Qa
y(Q - 67) = 93 - Qa
y =\frac{93-Qa}{Q-67}
olya-2409 [2.1K]4 years ago
6 0
<h2>Answer:</h2>

The value of y is:

           y=\dfrac{93-qa}{q-67}

<h2>Step-by-step explanation:</h2>

We are given a expression in terms of three unknowns q,a and y.

Now, we are asked to solve this expression for y.

i.e. we are asked to represent y in terms of other two unknowns.

We will first use the distributive property under multiplication in the left hand side of the equation.

i.e.

q\times a+q\times y=67y+93\\\\i.e.\\\\qa+qy=67y+93

Now, we combine the terms of y at one side of the equation and the other terms to the other side.

i.e.

qy-67y=93-qa\\\\i.e.\\\\(q-67)y=93-qa\\\\i.e.\\\\y=\dfrac{93-qa}{q-67}

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Dennis_Churaev [7]

Answer:

r = (3V/π)^1/3

Step-by-step explanation:

Given that :

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Dividing into 4

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V = 1/3πr³

Cross multiply

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Divide both sides by π

3V/ π = πr³/ π

3V/ π = r³

Take the cube root of both sides

r = (3V/π)^1/3

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3 years ago
Suppose y varies directly with x, and y=8 when x= -2. Find x when y=12
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Jessie is fencing in a rectangular plot outside of her back door so that she can let her dogs out to play. She has 60 feet of fe
DerKrebs [107]

Answer:

Dimensions are length 15 feet and width 30 feet.

Maximum area of the plot is 450 feet².

Step-by-step explanation:

Let the length of the plot = x feet and width = y feet.

Since, the amount of fencing to be applied on the three sides of the plot is 60 feet.

We have,

2x + y = 60 i.e. y=60-2x

Now, Area of the rectangular plot = Length × Width

i.e. Area of the rectangular plot = x \times y

i.e. Area of the rectangular plot = x\times (60-2x)

i.e. Area of the rectangular plot = -2x^2+60x

<em>Since, the maximum of the quadratic equation ax^2+bx+c will be obtained at x= \frac{-b}{2a}.</em>

Then, the maximum of the area of the plot is at the point x= \frac{-60}{2\times (-2)} i.e. x= 15

Then, maximum area of the rectangular plot = -2x^2+60x

i.e. maximum area of the rectangular plot = -2\times 15^2+60\times 15

i.e. maximum area of the rectangular plot = -450+900 = 450 feet²

Hence, Maximum area of the plot is 450 feet².

Then,y=60-2\times 15 implies y=60-30 i.e. y= 30.

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3 years ago
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Oksana_A [137]

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6 0
3 years ago
How many gallons of a 50% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 40% antif
Mariulka [41]

I don't know what the "six-step method" is supposed to be, so I'll just demonstrate the typical method for this problem.

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Each gal of the 50% solution used contributes 0.5 gal of antifreeze. Similarly, each gal of the 30% solution contributes 0.3 gal of antifreeze. So the new solution will contain (0.5 <em>x</em> + 0.3 * 60) gal = (0.5 <em>x</em> + 18) gal of antifreeze.

We want the concentration of antifreeze to be 40% in the new solution, so we need to have

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Solve for <em>x</em> :

0.5 <em>x</em> + 18 = 0.4 (<em>x</em> + 60)

0.5 <em>x</em> + 18 = 0.4 <em>x</em> + 24

0.5 <em>x</em> - 0.4 <em>x</em> = 24 - 18

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<em>x</em> = 6/0.1 = 60 gal

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