Answer: 79
Step-by-step explanation:
Line up the numbers from least to greatest. 39, 42, 44, 51, 55, 62, 66, 72, 77, 81, 94, 86 Then find the Median. Look at the upper part of the data set and from there find the 3rd quartile.
Answer:
Let the truck is driven X miles per day
Charges of company A will be = 90+0.4X
Charges of company B will be =30+0.7X
Let us find out value of X when charges of both companies are same
which means that 90+0.4 X= 30+0.7X
90-30 = 0.7X-0.4X
60 = 0.3X
60/0.3 = X
X= 200
The charges of both companies will be same if truck is driven 200 miles per day
Company A will have better deal if truck is driven more than 200 miles per day ( because per mile rate of company A is less than company B)
Step-by-step explanation:
Y = mx + b
4 = m(248) + b
6 = m(372) + b
subtract the two equations to get
-2 = m(-124) + 0
m = 1/62
Then plug in m into one of the equations to find b
4 = (1/62)(248) + b
4 = 4 + b
b = 0
So the equation is
y = (1/62)x + 0
or
y = (1/62)x
or
y = x/62
edit: I totally didn't use point slope. It should be
y + 0 = (1/62)(x + 0)
or y = (1/62)x
(since b is 0, that means she started driving directly at home)
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2) 150mi/1.25hr = Xmi/5hr
750mi/1.25 = X
X = 600miles
Usando un sistema de ecuaciones, se encuentra que la rapidez inicial del primer ninõ es 4.95 m/s.
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- Consideramos que la rapidez inicial de el primer ninõ es x, y de el segundo es y.
El primer niño rebota <u>1.5 veces más alto que el segundo</u>.
O sea:
La rapidez inicial del segundo niño es de 3.3 m/s.
Esto implica que 
¿Cuál es la rapidez (m/s) inicial del primer niño?
La rapidez inicial del primer ninõ es 4.95 m/s.
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