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Sonja [21]
3 years ago
5

M<6 = A. 53 degrees B. 100 degrees C. 127 degrees D. 130 degrees

Mathematics
1 answer:
FrozenT [24]3 years ago
7 0
C= 127 because 53+127= 180
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HELPPPPP: The average high temperatures each month in Dallas, Texas are shown in the chart. What value represents the 3rd 3rd qu
Sloan [31]

Answer: 79

Step-by-step explanation:

Line up the numbers from least to greatest. 39, 42, 44, 51, 55, 62, 66, 72, 77, 81, 94, 86 Then find the Median. Look at the upper part of the data set and from there find the 3rd quartile.

5 0
3 years ago
Read 2 more answers
Whoever answers first is brainliest
Mice21 [21]

Answer:

Let the truck is driven X miles per day

Charges of company A will be = 90+0.4X

Charges of company B will be =30+0.7X

Let us find out value of X when charges of both companies are same

which means that   90+0.4 X= 30+0.7X

                            90-30      = 0.7X-0.4X

                            60    = 0.3X

                             60/0.3 = X

                             X= 200

The charges of both companies will be same if truck is driven 200 miles per day

Company A will have better deal if truck is driven more than 200 miles per day ( because per mile rate of company A is less than company B)

Step-by-step explanation:

4 0
3 years ago
PLEASE HELP ME. :( :(
STatiana [176]
Y = mx + b

4 = m(248) + b
6 = m(372) + b
subtract the two equations to get
-2 = m(-124) + 0
m = 1/62

Then plug in m into one of the equations to find b
4 = (1/62)(248) + b
4 = 4 + b
b = 0

So the equation is
y = (1/62)x + 0
or
y = (1/62)x
or
y = x/62

edit: I totally didn't use point slope. It should be
        y + 0 = (1/62)(x + 0)
        or  y = (1/62)x

(since b is 0, that means she started driving directly at home)
-------------------
2) 150mi/1.25hr = Xmi/5hr
    750mi/1.25 = X
    X = 600miles
7 0
3 years ago
Read 2 more answers
Dos niños brincan en dos trampolines. El primer niño rebota 1.5 veces más alto que el segundo. La rapidez inicial del segundo ni
luda_lava [24]

Usando un sistema de ecuaciones, se encuentra que la rapidez inicial del primer ninõ es 4.95 m/s.

-------------------------

  • Consideramos que la rapidez inicial de el primer ninõ es x, y de el segundo es y.

El primer niño rebota <u>1.5 veces más alto que el segundo</u>.

O sea:

x = 1.5y

La rapidez inicial del segundo niño es de 3.3 m/s.

Esto implica que y = 3.3

¿Cuál es la rapidez (m/s) inicial del primer niño?

x = 1.5y = 1.5(3.3) = 4.95

La rapidez inicial del primer ninõ es 4.95 m/s.

Un problema similar es dado en brainly.com/question/24646137

3 0
3 years ago
1 Expand and simplify each expression<br> a) x(x+2)+x(x+5)
Vladimir [108]
X^2 + 2x + x^2 + 5x

2x^2 + 7x
3 0
3 years ago
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