Need help with 7 & 8. Show work please

Mathematics

1 answer:

salantis [7]3 years ago

7 0

The midpoint is ((x1+x2)/2, (y1+y2)/2)). For the first one, we have (3+3)/2=3 for the x value, and (1+7)/2=4 for the y value. I challenge you to do 8 on your own!

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Oxana [17]

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nikklg [1K]

Answer:

Assuming the numerator was 1.

$(6\sqrt{7}+1)/251$

Step-by-step explanation:

Assuming the numerator was 1.

$1/(6\sqrt{7} -1)\\ (6\sqrt{7}+1)/((6\sqrt{7} - 1)(6\sqrt{7} + 1))\\ (6\sqrt{7}+1)/((6\sqrt{7})^2 + 6\sqrt{7} - 7\sqrt{7} - 1)\\(6\sqrt{7}+1)/((6\sqrt{7})^2 - 1)\\(6\sqrt{7}+1)/((36*7 - 1)\\(6\sqrt{7}+1)/251$