Answer please i need help

Mathematics

1 answer:

Sauron [17]3 years ago

6 0

Answer:

oh my god

Step-by-step explanation:

why is your image blockedddd

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Rotate the object 90 degrees around the origin. What are the new coordinates?

amid [387]

Answer:

Step-by-step explanation:

6 0

3 years ago

Factor completely<br> (X^2 + x - 6) (2x^2 + 4x) =

Vikki [24]

Answer:

= 2x^4 + 6x^3 - 8x^2 + 24x

= 2x ( 2x^3 + 3x^2 - 4x + 12)

Step-by-step explanation:

(X^2 + x - 6) (2x^2 + 4x) =

Let's open the brackets carefully

x^2 * 2x^2 + x^2*4x + x*2x^2 + x*4x - 6*2x^2 - 24x

= 2x^4 + 4x^3 + 2x^3 + 4x^2 - 12x + 24x

= 2x^4 + 6x^3 - 8x^2 + 24x

= 2x ( 2x^3 + 3x^2 - 4x + 12)

8 0

3 years ago

A= [1, 3; 2, 1], B=[3, 6; -1, 1]. Find AB & BA if possible

steposvetlana [31]

Answer:

$AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}$

Step-by-step explanation:

For two matrix P and Q, the product, say PQ is defined when:

The number of columns of P = The number of rows of Q

Since A is a 2×2 matrix and B is also a 2×2 matrix

Thus both AB and BA are possible.

So AB is:

$AB\Rightarrow\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\\AB\Rightarrow\quad \begin{bmatrix}3\times 1+3\times (-1) & 6\times 1+3\times 1\\3\times 2+1\times (-1) & 6\times 2+1\times 1\end{bmatrix}\\AB\Rightarrow \quad \begin{bmatrix}0 & 9\\ 5 & 13\end{bmatrix}$

BA is:

$BA\Rightarrow\begin{bmatrix}3 & 6\\ -1 & 1\end{bmatrix}\begin{bmatrix}1 & 3\\ 2 & 1\end{bmatrix}\\BA\Rightarrow\quad \begin{bmatrix}3\times 1+6\times 2 & 3\times 3+6\times 1\\(-1)\times 1+1\times 2 & (-1)\times 3+1\times 1\end{bmatrix}\\BA\Rightarrow \quad \begin{bmatrix}15 & 15\\ 1 & -2\end{bmatrix}$