Answer:
Length = 5
Width = 21
Step-by-step explanation:
(x)(x + 16) = 105
x^2 + 16x = 105
x^2 + 16x - 105 = 0
(x - 5) x ( x + 21) = 0
x - 10 = 0
x = 5
x + 21 = 0
x = -21
Now that we have the zeroes.
We have to find the most viable one to put in.
Using -21 would not make sense, so we will use 5.
Plug it in:
x = 5
(5) (5 + 16) = 105
5 ( 21) = 105
×<_ 24 is the answer I believe.
<h3>
Answer: 8/25</h3>
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Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
Solution:
Given PRQ is a triangle.
ST is a line parallel to RQ.
<u>Triangle proportionality theorem,</u>
<em>If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.</em>
Do cross multiplication, we get
Divide by 2x on both sides, we get
