Well, for
her questionnaire she could use and create questions or queries that are
obviously related to her hypothesis or study.
These
could be done in a likert type of scale.
<span><span>
1.
</span>I read most often.
</span>
<span><span>a.
</span>Strongly Agree </span>
<span><span>b.
</span>Agree</span>
<span><span>c.
</span>Disagree </span>
<span><span>d.
</span>Strongly Disagree</span>
<span><span>
2.
</span>When I read my books its takes me 24 hours a day</span>
<span><span>
a.
</span>Strongly Agree </span>
<span><span>b.
</span>Agree</span>
<span><span>c.
</span>Disagree </span>
<span><span>d.
</span>Strongly Disagree</span>
<span><span>
3.
</span>When I start reading I can’t stop</span>
<span><span>
a.
</span>Strongly Agree </span>
<span><span>b.
</span>Agree</span>
<span><span>c.
</span>Disagree </span>
<span><span>d.
</span>Strongly Disagree</span>
Answer: B. (-6, 5)
Step-by-step explanation:
The Answer is 2/3
Steps: 1/4(1-(2/3^2+1/3)
Answer:
No, it is a value that is greater than 0
Step-by-step explanation:
A growth factor is indeed a value greater than 1 except it can be a decimal below 1 to. Therefore, a growth value is any POSITIVE number.
Answer:
The answer is "
"
Step-by-step explanation:
Given:

Find critical points:

differentiate the value with respect of x:
critical points
![\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3](https://tex.z-dn.net/?f=%5Cto%20%28x-e%29%5E2%20e%5E%7B%28e-x%29%7D%20%5Be%2B3-x%5D%3D0%5C%5C%5C%5C%5Cto%20e%5E%7B%28e-x%29%7D%5Cneq%200%20%5C%5C%5C%5C%5Cto%20%28x-e%29%5E2%3D0%5C%5C%5C%5C%20%5Cto%20%5Be%2B3-x%5D%3D0%5C%5C%5C%5C%5Cto%20x%3De%5C%5C%5C%5C%5Cto%20x%3De%2B3%5C%5C%5C%5C%5Cto%20x%3D%20e%2Ce%2B3)
So,
The critical points of 