<h3>
Answer: Choice B) 45/56</h3>
========================================================
Explanation:
When we divide two fractions like this, we flip the second fraction and multiply like so...

which points us to choice B as the answer.
The fraction 45/56 cannot be reduced further because 45 and 56 do not have any factors in common other than 1.
<u>Unit rate 4:</u>
The table
d n
4 1
8 2
16 4
<u>Unit rate 1/4:</u>
Table
d n
1 4
4 16
16 64
and
The equation n=4d
<u>Unit rate 16:</u>
Equation:
d = 16n
Step-by-step explanation:
The unit in the unit rate is dollars per unit ounces which means that the unit rate calculated by

So,
The first option is the equation:

The unit rate is 16 dollars per ounce
The second option is the table:
d n
1 4
4 16
16 64
We can take any pair of values of d and n from the table to calculate the unit rate
So taking
d = 1
n=4

The unit rate for table is: 1/4 dollars per ounces
Third option is the equation:
n = 4d

dividing both sides by n

dividing both sides by 4

the unit rate is 1/4 dollars per ounce
Fourth option is the table:
d n
4 1
8 2
16 4
We will take any pair of d and n to find the unit rate
So,
Taking
d = 4
n =1

The unit rate is 4 dollars per unit ounce.
Keywords: Unit rate, units
Learn more about unit rate at:
#LearnwithBrainly
Answer:
D. 8x=16
Step-by-step explanation:
If y=2x, then
2x+3y=16
2x+3(2x) =16
2x +6x=16
8x=16
Answer:
C
Step-by-step explanation:
The Hypotenuse is y
The side opposite the given angle (60o) is 12.
You must use one of the trig functions to relate the angle, the side opposite and the hypotenuse.
It turns out that the function you need to use is the sine.
angle = 60o
Side opposite = 12 cm
hypotenuse = h = ???
Sin(60o) = opposite / hypotenuse multiply both sides by the hypotenuse.
hypotenuse * sin(60o) = side opposite
Divide by sin(60o)
hypotenuse = side opposite / sin(60)
hypotenuse = 12/sin(60)
Sin(60) radical form = sqrt(3)/2
hypotenuse = 12 // sqrt(3)/2
hypotenuse = 24 // sqrt(3) Rationalize the denominator.
hypotenuse = 24 * sqrt(3) // ( (sqrt(3)*sqrt(3) )
hypotenuse = 8 sqrt(3)
C