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Vadim26 [7]
3 years ago
9

-4x - 16y=27 2x + 8y=-12

Mathematics
1 answer:
Gnesinka [82]3 years ago
6 0

Answer:

X=-10  Y=0,5

X=2  Y=-2

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Geometry..already got hw
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the second option

Step-by-step explanation:

Line CD is parallel to line AB, shown by the arrows in the middle of both of the lines.

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3 years ago
Can someone help me with this question??
maksim [4K]

Answer:

QT < TR.

Step-by-step explanation:

QT = TR because TZ is a mid segment so QT < TR is false.

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4 years ago
Least common multiple of z^2+6z+9 and z^2+z-6
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3 years ago
The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

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Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

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\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

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3 years ago
Jamaal bounces on a trampoline. His height, as a function of time, is modeled by y = -6x2 + 20x +4
kykrilka [37]

Answer: The function is no linear

Step-by-step explanation:

5 0
3 years ago
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